[英]Three.js grid Axis label issue and how to plot x,y,z data on the grid
我应该在3D网格上绘制井偏差调查。 借助网络上的几篇文章,我完成了具有所需大小的3D网格。 我现在面临的当前问题是x,y和z轴的标签已粘贴到网格上,而不是在场景中放错了位置。
var labelsH = labelAxis(height, data.labels.y,"y");
labelsH.position.x = width;
labelsH.position.y = - height +(2*height/a)-20;
labelsH.position.z = depth;
scene.add(labelsH);
function labelAxis(width, data, direction){
var separator = 2*width/data.length,
p = {
x:0,
y:0,
z:0
},
dobj = new THREE.Object3D();
for ( var i = 0; i < data.length; i ++ ) {
var label = makeTextSprite(data[i]);
label.position.set(p.x,p.y,p.z);
dobj.add( label );
if (direction=="y"){
p[direction]+=separator;
}else{
p[direction]-=separator;
}
//console.log(p.x+":"+p.y+":"+p.z)
}
return dobj;
}
有关完整的代码示例,请参见https://jsfiddle.net/3tw3dt1u/ 。
此外,我需要绘制的数据已经在上面提到的jsFiddle中。 由于JavaScript技能最少,我不知道如何将这些数据绘制在网格上以形成如下形式:
提前非常感谢您的帮助。
您的问题是关于点的绘制,这是如何完成的:
关键点如下。
// Not necessary, but I prefer to use the same scale as they use in their example. It's also easier since the data is according to those scales.
var graphDimensions = {
w:3000,
d:3000,
h:7000
};
var vectors = realData.map(function(d) { // Create vectors from your data
return new THREE.Vector3(d[0], d[1], d[2]);
});
var curve = new THREE.CatmullRomCurve3(vectors); // Create a curve with the vectors created above
var material = new THREE.LineBasicMaterial({color: "blue"}); // Material for the curve
var geometry = new THREE.Geometry();
var splinePoints = curve.getPoints(5000); // The 5000 in here is the resolution (number of points) on the curve. Increase for a smoother curve, decrease for a more jagged curve.
for (var i = 0; i < splinePoints.length; i++) { // Loop through the points to create vertices in the geometry
geometry.vertices.push(splinePoints[i]);
}
var line = new THREE.Line(geometry, material); // Create a line with your geometry and material
scene.add(line); // Add it to the scene
line.rotateX(Math.PI / 2); // Orient the line correctly
boundingGrid.position.set(0, -3.5, 1.5); // Move the grid into position
boundingGrid.scale.set(0.001, 0.001, 0.001); // Reduce by whatever scale you want to decrease it in size (otherwise you have to scroll out forever)
line.scale.set(0.001, 0.001, 0.001);
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