Oracle SQL-将来自多个表的结果集中的同一列中的值合并

Question

我很想知道如何合并来自两个不同表的同一列中的多个记录。 例如下面是我的表：

注释表：

INVOICE NOTES
1000    REPLACE PUMP
1000    REPLACE OIL
1000    REPLACE FILTER
1111    WO# 123
1111    REPLACE GASKET
1234    REPLACE OIL

发票表：

INVOICE AMOUNT
1000    100
1111    50
1234    20

我可以运行此查询和结果：

SELECT INV.INVOICE, INV.AMOUNT FROM INVOICE INV
INNER JOIN NOTES ON INV.INVOICE = NOTES.INVOICE

但我想将每个发票的注释合并到结果集中的一栏中。 例如，我的结果应如下所示

INVOICE  AMOUNT     NOTES
1000     100        REPLACE PUMP, REPLACE OIL, REPLACE FILTER
1111     50         WO# 123,REPLACE GASKET
1234     20         REPLACE OIL

Answer 1

文档-listagg

询问

with inv_notes as
(select 1000 as INVOICE, 'REPLACE PUMP' as notes from dual union all
select 1000, 'REPLACE PUMP' from dual union all
select 1000, 'REPLACE OIL' from dual union all
select 1000, 'REPLACE FILTER' from dual union all
select 1111, 'WO# 123' from dual union all
select 1111, 'REPLACE GASKET' from dual union all
select 1234, 'REPLACE OIL' from dual
) 
,
inv_amount as (
select 1000 as INVOICE, 100 AMOUNT from dual union all
select 1111, 50 from dual union all
select 1234, 20 from dual)
select a.invoice, a.amount, listagg(n.notes, ',') WITHIN GROUP (ORDER BY a.invoice, a.amount) notes
from inv_notes n
 inner join inv_amount a on n.invoice = a.invoice
group by a.invoice, a.amount 

结果

1   1000    100 REPLACE FILTER,REPLACE OIL,REPLACE PUMP,REPLACE PUMP
2   1111    50  REPLACE GASKET,WO# 123
3   1234    20  REPLACE OIL