[英]Print non-printable characters as fullstop in Java
我有一个十六进制字符串,需要将其转换为ASCII并进行打印。 在调试时,我可以看到正确的值,但是当我尝试打印ASCII时,它将忽略它并移至下一个。 有没有一种方法可以将所有不可打印的字符替换为dot(。)。 这是我的片段:
import javax.xml.bind.DatatypeConverter;
byte[] out = toByteArray("0000005401F40000D9E3C60500000000002000000000000000D7C8F10000000000000000000000004040404040404040D9E3C600E9C7C9F0F0F0F1F1E5D9C1D1C1D54040F0F0F14BF0F0F14BF0F0F14BF0F0F100"); // Input Hex String
System.out.println("ASCII: " + out); // Prints [B@15db9742
String hex = toHexString(out);
System.out.println("Hex: " + hex); // Prints the hex - 00000054 exactly
public static String toHexString(byte[] array) {
return DatatypeConverter.printHexBinary(array);
}
public static byte[] toByteArray(String s) {
return DatatypeConverter.parseHexBinary(s);
}
import java.util.Arrays;
import javax.xml.bind.DatatypeConverter;
public class Main {
public Main() {
// TODO Auto-generated constructor stub
}
public static void main(String[] args) {
byte[] out = toByteArray("0000005401F40000D9E3C60500000000002000000000000000D7C8F10000000000000000000000004040404040404040D9E3C600E9C7C9F0F0F0F1F1E5D9C1D1C1D54040F0F0F14BF0F0F14BF0F0F14BF0F0F100"); // Input Hex String
System.out.println("ASCII: " + Arrays.toString(out));
String hex = toHexString(out);
System.out.println("Hex: " + hex); // Prints the hex - 00000054 exactly
}
public static String toHexString(byte[] array) {
return DatatypeConverter.printHexBinary(array);
}
public static byte[] toByteArray(String s) {
return DatatypeConverter.parseHexBinary(s);
}
}
产量
替换示例:
//non-ASCII
String yourstring = Arrays.toString(out).replaceAll("[^\\x00-\\x7F]", ".");
//non-printable characters
String yourstring = Arrays.toString(out).replaceAll("\\p{C}", ".");
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