[英]How can I construct a java.security.PublicKey object from a base64 encoded string?
[英]From String to java.security.PublicKey object gaves me an illegal character
我有这种方法:
public static PublicKey getKey(String key){
try{
byte[] byteKey = Base64.getDecoder().decode(key.getBytes());
X509EncodedKeySpec X509publicKey = new X509EncodedKeySpec(byteKey);
KeyFactory kf = KeyFactory.getInstance("RSA");
return kf.generatePublic(X509publicKey);
}
catch(Exception e){
e.printStackTrace();
}
return null;
}
}
这应该转换一个公共密钥(此JSON中来自Salesforce公共密钥端点的n个属性之一)。 我的钥匙应该是208小子,但是:
getKey("pTSWJvy04hAU7ev7wmaTvpwHsEbseuPl0AlwoxPHnmoOIMATRT0eTqYpLJxDp4BHRFxDTrcUKHKVHGIAVut_-l6nkEI6ALOVW9C5PP9bXwqeHJ5tiGA6AMpaY1LsJJOd2lgExr0LHUPF2TtO4LOVmlptyGPTRSWhmRpPSc5bjGFsyTFr78WmeixjEts9icAUCiBDdpwVw9qVdjJPsufyimqp8os5htm-DB_qKsnRwABVSQRKLw2y7Mr7NP31R07Mpr108dLS5Et8tKnFoiX0MHf5BbA50NG3DtyT27nSa14T0IvSWYJQhxPWXYtuXkVldpbZZn8E2B1VpcDXXGnSPXoPstE9BU7w1RaF31UeEsE8sWDFdHgJMUYMfWjxVhdJB_NaVUt7v0X9QPffXcFPWKUUeVx0g_ONMz0bB_HltFSODWJeAvcZXk14u4sjpKXNIiK8dJzMe0Qn10m5nIdVtxzXfKHiDNobX1dMENDplhDMVk1eYS9x8dh90qt68Q59vKusm6iMjSaXtzwMfqJBwNck41e9Pie2m_cdSu-RIq1u3FScGkezzqNvIuzcse2y-6ApHkkaFMVsNw3CbD87LtVgNusuom38UVC1rS0LeLYFinU3hnFwvB1UCv1_0Cs8CmrOmdifqd25aZIDf5p8f3kowq3QY1mNtdQc9-HgZ3k");
返回一个错误:
java.lang.IllegalArgumentException:java.util.Base64 $ Decoder.decode0(Base64.java:714)处的base64字符5f在testJwt.testJwt.App处的java.util.Base64 $ Decoder.decode(Base64.java:526)处.getKey(App.java:52)在testJwt.testJwt.App.main(App.java:76)
我能做什么? 我做错了吗?
您拥有的数据不是完整的RSA公钥,而仅仅是模数或“ n”值。 “ e”值是公用密钥的另一部分。 这是代码片段来说明它。
import java.math.BigInteger;
import java.security.KeyFactory;
import java.security.PublicKey;
import java.security.spec.RSAPublicKeySpec;
import java.util.Base64;
public class Main {
public static void main(String[] args) throws Exception {
String jsonN = "pTSWJvy04hAU7ev7wmaTvpwHsEbseuPl0AlwoxPHnmoOIMATRT0eTqYpLJxDp4BHRFxDTrcUKHKVHGIA" +
"Vut_-l6nkEI6ALOVW9C5PP9bXwqeHJ5tiGA6AMpaY1LsJJOd2lgExr0LHUPF2TtO4LOVmlptyGPTRSWhmRpPSc5" +
"bjGFsyTFr78WmeixjEts9icAUCiBDdpwVw9qVdjJPsufyimqp8os5htm-DB_qKsnRwABVSQRKLw2y7Mr7NP31R0" +
"7Mpr108dLS5Et8tKnFoiX0MHf5BbA50NG3DtyT27nSa14T0IvSWYJQhxPWXYtuXkVldpbZZn8E2B1VpcDXXGnSP" +
"XoPstE9BU7w1RaF31UeEsE8sWDFdHgJMUYMfWjxVhdJB_NaVUt7v0X9QPffXcFPWKUUeVx0g_ONMz0bB_HltFSO" +
"DWJeAvcZXk14u4sjpKXNIiK8dJzMe0Qn10m5nIdVtxzXfKHiDNobX1dMENDplhDMVk1eYS9x8dh90qt68Q59vKu" +
"sm6iMjSaXtzwMfqJBwNck41e9Pie2m_cdSu-RIq1u3FScGkezzqNvIuzcse2y-6ApHkkaFMVsNw3CbD87LtVgNu" +
"suom38UVC1rS0LeLYFinU3hnFwvB1UCv1_0Cs8CmrOmdifqd25aZIDf5p8f3kowq3QY1mNtdQc9-HgZ3k";
String jsonE = "AQAB";
byte [] nBytes = Base64.getUrlDecoder().decode(jsonN);
byte [] eBytes = Base64.getUrlDecoder().decode(jsonE);
BigInteger n = new BigInteger(1, nBytes); // need to use the sign-magnitude constructor
BigInteger e = new BigInteger(1, eBytes);
RSAPublicKeySpec rsaPublicKeySpec = new RSAPublicKeySpec(n, e);
KeyFactory rsaKeyFactory = KeyFactory.getInstance("RSA");
PublicKey rsaPub = rsaKeyFactory.generatePublic(rsaPublicKeySpec);
System.out.println(rsaPub);
}
}
我不会手动执行此操作,而是寻找已经执行此操作的库,尽管库建议在stackoverflow上是不合时宜的。
您在Base64字符串中似乎有_
和-
(而不是/
和+
)。 然后它是URL安全编码的Base64:
Base64.getUrlDecoder().decode(key.getBytes())
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