JSON.parse中允许哪些字符？

Question

因此，在收到我的回复后，我不断收到解析错误。 有非法字符吗？

这是回应

[{"businessID": ChIJ49DlQ5NiwokRQ_noyKqlchQ,"latitude": 40.733038,"longitude":-73.6840691,"address":"1201
Jericho Turnpike, New Hyde Park","businessname":"SUBWAY®Restaurants"},{"businessID": ChIJZfl6R5NiwokRZo7PU4NPoMY
,"latitude": 40.7329359,"longitude":-73.684513,"address":"1113 Jericho Turnpike, New Hyde Park","businessname"
:"Gino's"},{"businessID": ChIJcbpnRJNiwokRrtbOKe7HQo0,"latitude": 40.733049,"longitude":-73.684006,"address"
:"1203 Jericho Turnpike, New Hyde Park","businessname":"Wong's Garden"},]

这是我处理响应的函数。 我肯定知道它在警报之前中断了，因为没有触发警报

var datad = $(msg).text();
    console.log(datad);
    var resultstring = datad.replace(',]',']');
    var JsonParseData = JSON.parse(resultstring);
        alert(JsonParseData); ///BREAKING BEFORE THIS LINE

Answer 1

几个错误。

1. 需要在双引号（ " ）中放入字符串。将"businessID": ChIJ49DlQ5NiwokRQ_noyKqlchQ替换为"businessID":"ChIJ49DlQ5NiwokRQ_noyKqlchQ"

2. 取出,在下面一行的末尾"businessname":"Wong's Garden"},]

Answer 2

JSON的键值需要用引号引起来。 JSON数据中的引号较少，最后还有一个逗号和一个回车

像这样是正确的：

[{"businessID":"ChIJ49DlQ5NiwokRQ_noyKqlchQ","latitude":"40.733038","longitude":"-73.6840691","address":"1201 Jericho Turnpike, New Hyde Park","businessname":"SUBWAY®Restaurants"},{"businessID":"ChIJZfl6R5NiwokRZo7PU4NPoMY","latitude":"40.7329359","longitude":"-73.684513","address":"1113 Jericho Turnpike, New Hyde Park","businessname":"Gino's"},{"businessID":"ChIJcbpnRJNiwokRrtbOKe7HQo0","latitude":"40.733049","longitude":"-73.684006","address":"1203 Jericho Turnpike, New Hyde Park","businessname":"Wong's Garden"}]

Answer 3

您的响应是无效的json格式，原因有两个：

• “ businessID”的值需要用引号引起来。
• JSON的最后一个对象后不应有逗号（您的替换字符串函数可解决此问题）。

我建议您使用以下JSON工具包：

• http://jsonviewer.stack.hu/ （这是我订购的json，尽管不正确）
• https://jsonformatter.org/ （我经常使用，我很喜欢）