在Javascript中对表格的列进行排序无法正常工作

Question

我从w3schools获得以下Javascript函数来对列进行排序：

function sortTable(n) {
  var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
  table = document.getElementById("myTable");
  switching = true;
  //Set the sorting direction to ascending:
  dir = "asc"; 
  /*Make a loop that will continue until
  no switching has been done:*/
  while (switching) {
    //start by saying: no switching is done:
    switching = false;
    rows = table.getElementsByTagName("TR");
    /*Loop through all table rows (except the
    first, which contains table headers):*/
    for (i = 1; i < (rows.length - 1); i++) {
      //start by saying there should be no switching:
      shouldSwitch = false;
      /*Get the two elements you want to compare,
      one from current row and one from the next:*/
      x = rows[i].getElementsByTagName("TD")[n];
      y = rows[i + 1].getElementsByTagName("TD")[n];
      /*check if the two rows should switch place,
      based on the direction, asc or desc:*/
      if (dir == "asc") {
        if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
          //if so, mark as a switch and break the loop:
          shouldSwitch= true;
          break;
        }
      } else if (dir == "desc") {
        if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
          //if so, mark as a switch and break the loop:
          shouldSwitch= true;
          break;
        }
      }
    }
    if (shouldSwitch) {
    /*If a switch has been marked, make the switch
    and mark that a switch has been done:*/
    rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
    switching = true;
    //Each time a switch is done, increase this count by 1:
    switchcount ++;      
    } else {
      /*If no switching has been done AND the direction is "asc",
      set the direction to "desc" and run the while loop again.*/
      if (switchcount == 0 && dir == "asc") {
        dir = "desc";
        switching = true;
      }
    }
  }
}

但是，在我称为Internet Explorer版本的专栏上，它不能很好地工作。

它与我的表的其他列配合良好。 我不知道为什么会这样。 有人可以告诉我怎么了吗？

我将这些值复制到excel工作表上，并试图对其进行排序，但是它也没有正确排序。 值有问题吗？

它只是考虑数字的第一个数字然后进行排序。 我怎样才能解决这个问题？

Answer 1

根据字符串操作比较规则，结果是正确的，但是您的要求有所不同。

字符串比较如何发生？ A <B

1. 它比较两个字符串的第一位的UTF-16值是否相等，然后比较下一个字符。

2. 如果A的字符串字符在某个点上小于B，则A字符串会更小。

3. 如果任何字符串将在得出结论之前结束，则将其视为小字符串。

例如

1. “ 10.0.9200.17609” <“ 11.0.15063.0” = true，因为第二个数字0 <1
2. “ 9” <“ 101” =否，因为UTF-16值'9'大于'1'
3. “ 101” <“ 1011” = true，因为直到3个字符都相等并且第一个字符串结束，所以它较小。

对于您的问题，您需要在[[，0，9200，17609]拆分后在。（点）上拆分数字，例如“ 10.0.9200.17609”，然后需要使用以下比较器函数来确定排序算法中哪个元素较小。

/** 
  A and B will be array and element are integer
  return true if A < B else false
**/
function comparator(A, B) {
   var a_length = A.length, b_length = B.length;
   var loop_count = min(a_length, b_length);
   for(var i = 0; i < loop_count; i++) {
     if(A[i] < B[i])
        return true;
     else if (A[i] > B[i])
        return false;
   }

   if(a_length < b_length)
     return true;

   return false;
}

Answer 2

简而言之，使用100000创建填充，例如

8.00.6001.18372 => 100008.100000.106001.118372
11.0.15063.0 => 100011.100000.115063.100000

与正则表达式

x = x.innerHTML.replace(/\d+/g, n => +n + 100000);

 function sortTable(n) { var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0; table = document.getElementById("myTable"); switching = true; //Set the sorting direction to ascending: dir = "asc"; /*Make a loop that will continue until no switching has been done:*/ // get longest version characters for padding var padding = '000000000000'; // 12 chars while (switching) { //start by saying: no switching is done: switching = false; rows = table.getElementsByTagName("TR"); /*Loop through all table rows (except the first, which contains table headers):*/ for (i = 1; i < (rows.length - 1); i++) { //start by saying there should be no switching: shouldSwitch = false; /*Get the two elements you want to compare, one from current row and one from the next:*/ x = rows[i].getElementsByTagName("TD")[n]; y = rows[i + 1].getElementsByTagName("TD")[n]; /*check if the two rows should switch place, based on the direction, asc or desc:*/ // the hack, remove dot x = x.innerHTML.replace(/\\d+/g, n => +n + 100000); y = y.innerHTML.replace(/\\d+/g, n => +n + 100000); //console.log(x) if (dir == "asc") { if (x > y) { //if so, mark as a switch and break the loop: shouldSwitch = true; break; } } else if (dir == "desc") { if (x < y) { //if so, mark as a switch and break the loop: shouldSwitch = true; break; } } } if (shouldSwitch) { /*If a switch has been marked, make the switch and mark that a switch has been done:*/ rows[i].parentNode.insertBefore(rows[i + 1], rows[i]); switching = true; //Each time a switch is done, increase this count by 1: switchcount++; } else { /*If no switching has been done AND the direction is "asc", set the direction to "desc" and run the while loop again.*/ if (switchcount == 0 && dir == "asc") { dir = "desc"; switching = true; } } } } document.querySelector('#thead').addEventListener('click', function() { sortTable(0); }) 

 table { border: 1px solid #dddddd; width: 60%; border-collapse: collapse; } th { background-color: #209d9d; cursor: pointer; } th:hover { background-color: #1c8d8d; } tr { height: 30px; } th, td { text-align: center; border-collapse: collapse; width: 60%; border: 1px solid #ddd; align: center } 

 <table id="myTable"> <tr><th id="thead">IE Versions</th></tr> <tr><td>10.0.8250.00000</td></tr> <tr><td>10.0.8400.00000</td></tr> <tr><td>10.0.9200.16384</td></tr> <tr><td>8.00.6001.18372</td></tr> <tr><td>8.00.6001.18702</td></tr> <tr><td>8.00.7000.00000</td></tr> <tr><td>8.00.7600.16385</td></tr> <tr><td>9.0.8080.16413</td></tr> <tr><td>9.0.8112.16421</td></tr> <tr><td>10.0.9200.17609</td></tr> <tr><td>11.0.15063.0</td></tr> <tr><td>11.0.9600.18697</td></tr> <tr><td>8.00.6001.18241</td></tr> </table>