[英]Returning the sum of a select statement SQL
我创建了一个SELECT语句:
SELECT ARII2.Amount
FROM
AR_Customer ARC2
Inner JOIN AR_Customer_Site ARCS2 On ARC2.Customer_Id = ARCS2.Customer_Id AND ARCS2.Customer_Id = ARC2.Customer_Id
INNER JOIN AR_Customer_System ARCSYS2 On ARCS2.Customer_Site_Id = ARCSYS2.Customer_Site_Id
INNER JOIN AR_Branch ARB2 ON ARB2.Branch_Id = ARC2.Branch_Id
INNER JOIN AR_Invoice ARIN2 ON ARIN2.Customer_Site_Id = ARCS2.Customer_Site_Id
INNER JOIN AR_Invoice_Item ARII2 ON ARII2.Invoice_Id = ARIN2.Invoice_Id
Inner JOIN SY_System SYSY2 On ARCSYS2.System_Id = SYSY2.System_Id
WHERE
ARIN2.Invoice_Date > dateadd(year, -1, getdate())
AND ARC2.Customer_Number = '300000'
AND ARII2.[Description] LIKE ('Warranty Credit')
OR ARII2.[Description] = ('Warranty Credit T')
GROUP BY ARII2.Amount
返回以下结果。
2031.00
1458.98
1272.50
620.00
160.00
我的想法是,我可以对我的金额加上一个SUM,它将返回期望值5542.48(这些值的总和)。
SELECT
SUM(ARII2.Amount)
FROM
AR_Customer ARC2
Inner JOIN AR_Customer_Site ARCS2 On ARC2.Customer_Id = ARCS2.Customer_Id AND ARCS2.Customer_Id = ARC2.Customer_Id
INNER JOIN AR_Customer_System ARCSYS2 On ARCS2.Customer_Site_Id = ARCSYS2.Customer_Site_Id
INNER JOIN AR_Branch ARB2 ON ARB2.Branch_Id = ARC2.Branch_Id
INNER JOIN AR_Invoice ARIN2 ON ARIN2.Customer_Site_Id = ARCS2.Customer_Site_Id
INNER JOIN AR_Invoice_Item ARII2 ON ARII2.Invoice_Id = ARIN2.Invoice_Id
Inner JOIN SY_System SYSY2 On ARCSYS2.System_Id = SYSY2.System_Id
WHERE
ARIN2.Invoice_Date > dateadd(year, -1, getdate())
AND ARC2.Customer_Number = '300000'
--AND ARIN2.Invoice_Number = '204686'
AND ARII2.[Description] LIKE ('Warranty Credit')
OR ARII2.[Description] = ('Warranty Credit T')
GROUP BY ARII2.Amount, ARII2.[Description]
返回的结果不是我想要的结果。
-10155.00
-7294.90
-6362.50
-3100.00
-800.00
一如既往,对此的任何帮助均深表感谢!
由于GROUP BY,您将获得多行。 删除该行,您将只得到一个总计SUM。
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