我从脚本到jsoup都无法获得价值
[英]I can't get value from script to jsoup
问题描述
我想编码以获取价值流，但失败了。
如何获得价值流： http ://123.30.215.65/hls/4545780bfa790819/5/3/d836ad614748cdab11c9df291254cf836f21144da20bf08142455a8735b328ca/dnR2MQ==_m.m3u8使用Jsoup吗？
<html> <head> <style>html,body{margin:0;padding:0;background:#000;;}</style> <meta charset="utf-8"> <script src="https://code.jquery.com/jquery-2.1.4.js"></script> <script type="text/javascript" src="https://cdn.jsdelivr.net/clappr/latest/clappr.min.js"></script> <meta name="referrer" content="no-referrer"> </head> <body> <div style="width: 100%;"> </div> <div id="player"></div> <script> player = new Clappr.Player({source: "http://123.30.215.65/hls/4545780bfa790819/5/3/d836ad614748cdab11c9df291254cf836f21144da20bf08142455a8735b328ca/dnR2MQ==_m.m3u8", parentId: '#player', width: '100%', height: "100%", hideMediaControl: true, autoPlay: true }); </script> </body> </html>
Java代码我：
Elements script = doc.select("script");
Pattern p = Pattern.compile("player = new Clappr.Player(\\(\"source:{\", \"(.*)\", false\\)");
// ^^ is the capturing group
String url = "";
for (Element element : script) {
Matcher m = p.matcher(element.data());
if (m.find()){
url = m.group(1);
}
}
System.out.println(url);
1 个解决方案
解决方案1
0 2017-07-26 12:08:48
嗨，在您的代码中尝试一下，
String ResultString = null;
try {
Pattern regex = Pattern.compile("source:\\s[\"](.*?[^\\\\])[\"]", Pattern.DOTALL | Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE | Pattern.MULTILINE);
Matcher regexMatcher = regex.matcher(subjectString);
if (regexMatcher.find()) {
ResultString = regexMatcher.group(1);
}
} catch (PatternSyntaxException ex) {
// Syntax error in the regular expression
}
这就像一个魅力..！ :)
我可以从另一个脚本获取变量的值吗？
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