如何在 Spring Boot REST API 中捕获 AccessDeniedException

Question

我有一个带有 2 个端点的简单 Spring Boot REST API，一个受保护，一个不受保护。 对于受保护的，我想捕获AccessDeniedException并发送 401 而不是默认的 500 错误。 这是我的安全配置：

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter{

@Override
public void configure(WebSecurity webSecurity) {
    webSecurity.ignoring().antMatchers("/");
}

@Override
protected void configure(HttpSecurity http) throws Exception {
    http
            .exceptionHandling()
            .accessDeniedHandler(new AccessDeniedHandler() {
                @Override
                public void handle(HttpServletRequest request, HttpServletResponse response, org.springframework.security.access.AccessDeniedException accessDeniedException) throws IOException, ServletException {
                    System.out.println("I am here now!!!");
                }
            });

    http
            .addFilterAfter(getSecurityFilter(), FilterSecurityInterceptor.class);
    http
            .sessionManagement()
            .sessionCreationPolicy(SessionCreationPolicy.STATELESS);
    http
            .csrf()
            .disable();
    http
            .authorizeRequests()
            .antMatchers("/protected").anonymous();
}

public Filter getSecurityFilter() {
    return new Filter() {
        @Override
        public void init(FilterConfig filterConfig) throws ServletException {
            //do nothing here
        }

        @Override
        public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
            String appKeyHeaderValue = ((HttpServletRequest)request).getHeader("X-AppKey");
            if(appKeyHeaderValue!=null && appKeyHeaderValue.equals("MY_KEY")) {
                chain.doFilter(request,response);
            } else {
                throw new AccessDeniedException("Access denied man");
            }
        }

        @Override
        public void destroy() {

        }
    };
}

}

我从来没有看到我的I am here now!!! print 语句，我看到的是默认页面Whitelabel Error Page This application has no explicit mapping for /error, so you are seeing this as a fallback. Tue Jul 25 23:21:15 CDT 2017 There was an unexpected error (type=Internal Server Error, status=500). Access denied man Whitelabel Error Page This application has no explicit mapping for /error, so you are seeing this as a fallback. Tue Jul 25 23:21:15 CDT 2017 There was an unexpected error (type=Internal Server Error, status=500). Access denied man Whitelabel Error Page This application has no explicit mapping for /error, so you are seeing this as a fallback. Tue Jul 25 23:21:15 CDT 2017 There was an unexpected error (type=Internal Server Error, status=500). Access denied man注意我的Access denied man是如何在抛出异常时打印出来的。

当我运行项目时，我还在控制台中看到以下内容： 2017-07-25 23:21:14.818 INFO 3872 --- [ restartedMain] swsmmaRequestMappingHandlerMapping : Mapped "{[/error]}" onto public org.springframework.http.ResponseEntity<java.util.Map<java.lang.String, java.lang.Object>> org.springframework.boot.autoconfigure.web.BasicErrorController.error(javax.servlet.http.HttpServletRequest) 2017-07-25 23:21:14.818 INFO 3872 --- [ restartedMain] swsmmaRequestMappingHandlerMapping : Mapped "{[/error],produces=[text/html]}" onto public org.springframework.web.servlet.ModelAndView org.springframework.boot.autoconfigure.web.BasicErrorController.errorHtml(javax.servlet.http.HttpServletRequest,javax.servlet.http.HttpServletResponse)

这是我的项目结构的样子：

Answer 1

我使用一个自定义类扩展ResponseEntityExceptionHandler和一些注释。

你只需要像这样创建一个类：

@ControllerAdvice
public class CustomResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {

    @ExceptionHandler(AccessDeniedException.class)
    public final ResponseEntity<ErrorMessage> handleAccessDeniedException(AccessDeniedException ex, WebRequest request) {
        ErrorMessage errorDetails = new ErrorMessage(new Date(), ex.getMessage(), request.getDescription(false));
        return new ResponseEntity<>(errorDetails, HttpStatus.FORBIDDEN);
    }

}

在这种情况下，答案将类似于：

{
    "timestamp": "2018-12-28T14:25:23.213+0000",
    "message": "Access is denied",
    "details": "uri=/user/list"
}

Answer 2

正如@Afridi 所建议的那样，异常甚至在到达控制器之前就发生了，因此必须在过滤器链中进行处理。 我建议执行以下操作：

public class AccessDeniedExceptionFilter extends OncePerRequestFilter {

    @Override
    public void doFilterInternal(HttpServletRequest req, HttpServletResponse res, 
                                FilterChain fc) throws ServletException, IOException {
        try {
            fc.doFilter(request, response);
        } catch (AccessDeniedException e) {
         // log error if needed here then redirect
     RequestDispatcher requestDispatcher = 
             getServletContext().getRequestDispatcher(redirecturl);
     requestDispatcher.forward(request, response);

    }
}

添加此过滤器以过滤链

protected void configure(HttpSecurity http) throws Exception {
http
....
.addFilterAfter(httpClientFilter(), AccessDeniedExceptionFilter.class)