当从实时数据库中删除对象时，Firebase功能（用NodeJS编写）从云存储中删除文件

Question

我是NodeJS的新手，我正在尝试为Firebase的Cloud Functions编写下一个方法。

我想要实现的目标：

1. 当用户从Firebase DB中删除Photo对象时，应该触发该函数;
2. 代码应从与Photo obj对应的Storage中删除文件对象。

这些是我的Firebase数据库结构：

照片/ {userUID} / {} photoUID

{
"dateCreated":      "2017-07-27T16:40:31.000000Z",
"isProfilePhoto":   true,
"isSafe":           true,
"uid":              "{photoUID}",
"userUID":          "{userUID}"
}

和Firebase存储格式：

照片/ {userUID} / {} photoUID .PNG

我正在使用的NodeJS代码：

    const functions = require('firebase-functions')
    const googleCloudStorage = require('@google-cloud/storage')({keyFilename: 'firebase_admin_sdk.json' })
    const admin = require('firebase-admin')
    const vision = require('@google-cloud/vision')();

    admin.initializeApp(functions.config().firebase)

    exports.sanitizePhoto = functions.database.ref('photos/{userUID}/{photoUID}')
        .onDelete(event => {

            let photoUID = event.data.key
            let userUID = event.data.ref.parent.key

            console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

            if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
                console.error('Error while sanitize photo, user uid or photo uid are missing');
                return
            }

            console.log(`Deleting photo: ${photoUID}`)

            googleCloudStorage.bucket(`photos/${userUID}/${photoUID}.png`).delete().then(() => {
                console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
            }).catch(err => {
                console.log(`Failed to remove photo, error: ${err}`)
            });

        });

当我运行它时，我得到下一个错误：“ApiError：Not found”

我认为代码的这些部分是导致问题的部分：

googleCloudStorage.bucket(`photos/${userUID}/${photoUID}.png`).delete()

提前感谢您的支持和耐心。

Answer 1

发现问题，这里的代码对我有用：

const functions = require('firebase-functions');

实时数据库：

exports.sanitizePhoto = functions.database.ref('photos/{userUID}/{photoUID}').onDelete(event => {

        let photoUID = event.data.key
        let userUID = event.data.ref.parent.key

        console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

        if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
            console.error('Error while sanitize photo, user uid or photo uid are missing');
            return
        }

        console.log(`Deleting photo: ${photoUID}`)

        const filePath = `photos/${userUID}/${photoUID}.png`
        const bucket = googleCloudStorage.bucket('myBucket-12345.appspot.com')
        const file = bucket.file(filePath)

        file.delete().then(() => {
            console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
        }).catch(err => {
            console.log(`Failed to remove photo, error: ${err}`)
        });

    });

这里是相同的代码，但对于Firestore（不确定它是否有效，因为我不是NodeJS开发人员，并且实际上没有测试它）：

exports.sanitizePhoto = functions.firestore.document('users/{userUID}/photos/{photoUID}').onDelete((snap, context) =>{

    const deletedValue = snap.data();

    let photoUID = context.params.photoUID 
    let userUID = context.params.userUID

    console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

    if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
        console.error('Error while sanitize photo, user uid or photo uid are missing');
        return
    }

    console.log(`Deleting photo: ${photoUID}`)

    const filePath = `photos/${userUID}/${photoUID}.png`
    const bucket = googleCloudStorage.bucket('myBucket-12345.appspot.com')
    const file = bucket.file(filePath)

    file.delete().then(() => {
        console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
    }).catch(err => {
        console.error(`Failed to remove photo, error: ${err}`)
    });

});

你也可以注意到我的路径改变了：

photos/{userUID}/{photoUID} 

至：

users/{userUID}/photos/{photoUID}

Answer 2

试试这个

const gcs  = require('@google-cloud/storage')()

    const fileBucketPush = 'Storage bucket.appspot.com'; // The Storage bucket that contains the file.
    const filePathPush = 'folder/'+nameImage; // File path in the bucket.
    vision.detectSafeSearch(gcs.bucket(fileBucketPush).file(filePathPush))
      .then((results) => {
       ..///

      })
      .catch((err) => {
        console.error('ERROR:', err);
      });

您启用Cloud Vision API？