在HttpURLConnection中使用PATCH方法时出错

Question

从最近的几个小时开始，我正在尝试使用HttpURLConnection PUT方法更新资源的某些字段。 但是现在我将其更改为PATCH 。

我能够执行GET和POST ，但是在Http方法PATCH不断出错。

该请求甚至没有在POSTMAN中发送。

这是java类：

try {
    String serUrl = "https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/255";
    String authString = user + ":" + password;
    byte[] authEncBytes = Base64.getEncoder().encode(authString.getBytes());
    String authStringEnc = new String(authEncBytes);

    URL url = new URL(serUrl); //Enter URL here
    HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
    httpURLConnection.setDoInput(true);
    httpURLConnection.setDoOutput(true);
    httpURLConnection.setRequestProperty("X-HTTP-Method-Override", "PATCH");
    httpURLConnection.setRequestMethod("POST");
    httpURLConnection.setRequestProperty("Authorization", "Basic " + authStringEnc);
    httpURLConnection.setRequestProperty("Content-Type", "application/json");

    httpURLConnection.connect();

    String inputJson = "{   \"id\":" + 255 + "," +
        "\"assignedToAccount\": {" +
        "     \"id\":" + 233 +
        " }," +
        " \"name\":\"" + "task2_checking34" + "\"," +
        " \"serviceSettings\":{" +
        "     \"incident\":{" +
        "         \"id\":" + 380 +
        "     }" +
        " }" +
        "}";
    OutputStreamWriter osw = new OutputStreamWriter(httpURLConnection.getOutputStream());
    osw.write(inputJson);
    osw.flush();
    osw.close();

    BufferedReader br = new BufferedReader(new InputStreamReader(
        (httpURLConnection.getInputStream())));

    String output;
    StringBuffer bfr = new StringBuffer();
    String res = "";
    System.out.println("Output from Server .... \n");
    while ((output = br.readLine()) != null) {
        bfr.append(output);
    }
    res = bfr.toString();

} catch (MalformedURLException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}

通过覆盖POST在HttpUrlConnection中使用PATCH方法的想法从这里得到。

我想到了在从此处获得的请求正文中发送参数的想法。

此URL上的可用资源https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/

{
    "id": 253,
    "lookupName": "task_quality34",
    "createdTime": "2017-08-03T05:34:34Z",
    "updatedTime": "2017-08-03T05:34:34Z",
    "links": [{
        "rel": "canonical",
        "href": "https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/253"
    }]
}, {
    "id": 255,
    "lookupName": "task_quality-test12",
    "createdTime": "2017-08-03T05:48:26Z",
    "updatedTime": "2017-08-03T05:48:26Z",
    "links": [{
        "rel": "canonical",
        "href": "https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/255"
    }]
}

我正在尝试使用此URL上的PATCH方法update此资源的某些字段https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/255

但是每次我得到错误

java.io.IOException: Server returned HTTP response code: 400 for URL: https://lavazzaindia--tst1.custhelp.com/services/rest/connect/latest/tasks/255
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source)
    at com.cloud.task.TaskUpdate.main(TaskUpdate.java:80)

请有人在这里帮助我解决此问题。

Answer 1

好吧，我在回答自己的问题。

我只修改了几行代码，它对我有用。 以下是工作代码：

        try {
            URL url = new URL(serUrl); //Enter URL here
            HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
            httpURLConnection.setDoOutput(true);
            httpURLConnection.setRequestMethod("POST");
            httpURLConnection.setRequestProperty("Authorization", "Basic " + authStringEnc);
            httpURLConnection.setRequestProperty("Accept", "application/json");
            httpURLConnection.setRequestProperty("Content-Type", "application/json");
            httpURLConnection.setRequestProperty("X-HTTP-Method-Override", "PATCH");
            httpURLConnection.connect();

            DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream());
            wr.write(inputJson.getBytes());
            wr.flush();
            BufferedReader br = new BufferedReader(new InputStreamReader(
                    (httpURLConnection.getInputStream())));


            StringBuffer bfr = new StringBuffer();
            String output = "";
            String res = "";

            while ((output = br.readLine()) != null) {
                bfr.append(output);
            }
            resCode = httpURLConnection.getResponseCode();
//            System.out.println("response code = "+resCode);
            if (resCode != 200) {
                throw new RuntimeException("Failed : HTTP error code : "
                        + resCode +"\n"
                        +bfr.toString());
            }
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

在变量inputJson当参数id已经存在于url中时，我们不应该发送它。

我一直在尝试使用示例程序的数量，最后资源正在更新。