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[英]Reading and inserting part of a csv file using php - not wanting repeating data
[英]How to hide repeating part of the retrieved data values using php and codeigniter
由于这个MySQL语句,我已经获得了下表
SELECT * FROM expenses, income
WHERE expenses.projectname=income.projectname
AND expenses.task=income.task
在此表中,一个项目有许多任务。 因此项目,客户,项目开始和结束日期列无意义地重复。 如何才能为所有任务显示一次? 如何在这里应用PHP隐藏逻辑? 下图显示了我需要实现的目标。 通过MySQL查询检索数据。 但是我怎样才能隐藏重复的不必要的值 这是CodeIgniter视图页面
<table class="table table-lg">
<thead >
<tr class="filters">
<th><input type="text" class="form-control" placeholder="Project" disabled></th>
<th><input type="text" class="form-control" placeholder="Employee" disabled></th>
<th><input type="text" class="form-control" placeholder="Task" disabled></th>
<th><input type="text" class="form-control" placeholder="Expense" disabled></th>
<th><input type="text" class="form-control" placeholder="Amount" disabled></th>
<th><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
<th><input type="text" class="form-control" placeholder="Client" disabled></th>
<th><input type="text" class="form-control" placeholder="Cost" disabled></th>
<th><input type="text" class="form-control" placeholder="Income " disabled></th>
<th><input type="text" class="form-control" placeholder="Date" disabled></th>
</tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
foreach ($view_data1 as $key => $data) {
?>
<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
<td><?php echo $data['projectname']; ?></td>
<td><?php echo $data['employee']; ?></td>
<td><?php echo $data['task']; ?></td>
<td><?php echo $data['ExpenseName']; ?></td>
<td><?php echo $data['ExpenseAmount']; ?></td>
<td><?php echo $data['pn']; ?></td>
<td><?php echo $data['cname']; ?></td>
<td><?php echo $data['taskcost']; ?></td>
<td><?php echo $data['amount']; ?></td>
<td><?php echo $data['datetimepicker_mask']; ?></td>
</tr>
<?php
$i++;
}
else:
?>
<tr>
<td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
endif;
?>
</tbody>
</table>
我没有测试这段代码,但想法是记住最后一个密钥(在这种情况下为projectname和employee),然后将它与当前密钥进行比较。
示例代码中的字段与您的Word文档示例表不匹配,因此我只使用了您的代码示例。
<tbody>
<?php
if (isset($view_data1) && is_array($view_data1) && count($view_data1)) {
$i = 1;
$last_key = '';
foreach ($view_data1 as $key => $data) {
$stripe = 'odd';
if ($i % 2 == 0) {
$stripe = 'even';
}
echo "<tr class='$stripe'>";
$i++;
$current_key = $data['projectname'] . $data['employee'];
if ($current_key !== $last_key) {
echo "<td>" . $data['projectname'] . "</td>";
echo "<td>" . $data['employee'] . "</td>";
} else {
echo "<td colspan='2'></td>";
}
$last_key = $current_key;
?>
<td><?php echo $data['task']; ?></td>
<td><?php echo $data['ExpenseName']; ?></td>
<td><?php echo $data['ExpenseAmount']; ?></td>
<td><?php echo $data['pn']; ?></td>
<td><?php echo $data['cname']; ?></td>
<td><?php echo $data['taskcost']; ?></td>
<td><?php echo $data['amount']; ?></td>
<td><?php echo $data['datetimepicker_mask']; ?></td>
</tr>
<?php
}
} else {
?>
<tr><td colspan="10" align="center" >No Records Found..</td></tr>
<?php
}
?>
</tbody>
</table>
当时不要选择两张桌子。 加入条件。
SELECT expenses.*,income.*,expenses.id as p_id FROM expenses
join income ON expenses.task=income.task AND expenses.projectname=income.projectname
改变你对foreach部分的看法
<table class="table table-lg">
<thead >
<tr class="filters">
<th ><input type="text" class="form-control" placeholder="Project" disabled></th>
<th ><input type="text" class="form-control" placeholder="Employee" disabled></th>
<th ><input type="text" class="form-control" placeholder="Task" disabled></th>
<th ><input type="text" class="form-control" placeholder="Expense" disabled></th>
<th ><input type="text" class="form-control" placeholder="Amount" disabled></th>
<th ><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
<th ><input type="text" class="form-control" placeholder="Client" disabled></th>
<th ><input type="text" class="form-control" placeholder="Cost" disabled></th>
<th ><input type="text" class="form-control" placeholder="Income " disabled></th>
<th ><input type="text" class="form-control" placeholder="Date" disabled></th>
</tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
$is_exists=array();
foreach ($view_data1 as $key => $data) {
?>
<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
<?php
if(!in_array($data['p_id'], $is_exists)){
$is_exists[]=$data['p_id'];
?>
<td><?php echo $data['projectname']; ?></td>
<td><?php echo $data['employee']; ?></td>
<td><?php echo $data['task']; ?></td>
<td><?php echo $data['ExpenseName']; ?></td>
<?php
}else{
echo "<td rowspan='4'></td>";
}
?>
<td><?php echo $data['ExpenseAmount']; ?></td>
<td><?php echo $data['pn']; ?></td>
<td><?php echo $data['cname']; ?></td>
<td><?php echo $data['taskcost']; ?></td>
<td><?php echo $data['amount']; ?></td>
<td><?php echo $data['datetimepicker_mask']; ?></td>
</tr>
<?php
$i++;
}
else:
?>
<tr>
<td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
endif;
?>
</tbody>
</table>
不要合并这样的表。 在模型中使用连接查询,并通过控制器在视图中调用它
public function getExpenses(){
$this->db->select("addexpense.exp_date, addexpense.exp_amount, addexpense.exp_note, addexpense.exp_created, addcategory.category_name");
$this->db->from('addexpense');
$this->db->join('addcategory', 'addcategory.category_id = addexpense.category_id');
$query = $this->db->get();
return $query->result();
}
如果我理解你,你可以试试以下。
<?php
$arrData = [
[
"projectname" => "First Project",
"employee" => "First Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 1",
"description" => "Description 1",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
[
"projectname" => "First Project",
"employee" => "First Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 2",
"description" => "Description 2",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
[
"projectname" => "First Project",
"employee" => "First Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 3",
"description" => "Description 3",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
[
"projectname" => "Second Project",
"employee" => "Second Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 4",
"description" => "Description 4",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
[
"projectname" => "Second Project",
"employee" => "Second Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 5",
"description" => "Description 5",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
[
"projectname" => "Second Project",
"employee" => "Second Client",
"projectstart" => "12-12-2017",
"projectend" => "12-12-2019",
"task" => "Task 6",
"description" => "Description 6",
"commission" => "1000",
"taststart" => "01-01-2018",
"taskend" => "10-01-2018"
],
];
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- The above 3 meta tags *must* come first in the head; any other head content must come *after* these tags -->
<title>Bootstrap 101 Template</title>
<!-- Bootstrap -->
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-1q8mTJOASx8j1Au+a5WDVnPi2lkFfwwEAa8hDDdjZlpLegxhjVME1fgjWPGmkzs7" crossorigin="anonymous">
<!-- HTML5 shim and Respond.js for IE8 support of HTML5 elements and media queries -->
<!-- WARNING: Respond.js doesn't work if you view the page via file:// -->
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/html5shiv/3.7.3/html5shiv.min.js"></script>
<script src="https://oss.maxcdn.com/respond/1.4.2/respond.min.js"></script>
<![endif]-->
</head>
<body>
<div class="container">
<table class="table table-striped table-hover">
<thead>
<tr>
<th>Project</th>
<th>Client</th>
<th>Project start on</th>
<th>Project end on</th>
<th>task</th>
<th>description</th>
<th>commission</th>
<th>task start on</th>
<th>task end on</th>
</tr>
</thead>
<tbody>
<?php
$strSavedProjectName = false;
foreach($arrData AS $arrItem)
{
?>
<tr>
<?php
if (!$strSavedProjectName || $strSavedProjectName!= $arrItem['projectname']) :
?>
<td><?=$arrItem['projectname']; ?>
<td><?=$arrItem['employee']; ?>
<td><?=$arrItem['projectstart']; ?>
<td><?=$arrItem['projectend']; ?>
<?php
else :
?>
<td colspan="4"></td>
<?php
endif;
?>
<td><?=$arrItem['task']; ?>
<td><?=$arrItem['description']; ?>
<td><?=$arrItem['commission']; ?>
<td><?=$arrItem['taststart']; ?>
<td><?=$arrItem['taskend']; ?>
</tr>
<?php
$strSavedProjectName = $arrItem['projectname'];
}
?>
</tbody>
</table>
</div>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js" integrity="sha384-0mSbJDEHialfmuBBQP6A4Qrprq5OVfW37PRR3j5ELqxss1yVqOtnepnHVP9aJ7xS" crossorigin="anonymous"></script>
</body>
</html>
这是一个完整的示例,基于您的数据 - 因此您应该能够轻松地将其转换为您的视图。
逻辑
我实现的隐藏逻辑按以下顺序工作:
HTML表和PHP如下所示:
<table border="1">
<thead>
<tr>
<th>Project</th>
<th>Client</th>
<th>Project Start</th>
<th>Project End</th>
<th>Task</th>
<th>Description</th>
<th>Commission</th>
<th>Task Start</th>
<th>Task End</th>
</tr>
</thead>
<tbody>
<!-- Initial Condition -->
<?php $the_project = "";?>
<!-- Main Loop -->
<?php foreach ($data as $x => $datum) { ?>
<tr>
<!-- Condition Check -->
<!-- If not the same with the last project, it will show the columns. -->
<!-- That's why the Initial Condition is empty so that the 1st time this Condition Check run will always result true. -->
<?php if($datum['project'] != $the_project) { ?>
<td><?php echo $datum['project'];?></td>
<td><?php echo $datum['client'];?></td>
<td><?php echo $datum['proj_start'];?></td>
<td><?php echo $datum['proj_end'];?></td>
<?php } else { ?>
<td colspan="4"> </td>
<?php } ?>
<!-- /Condition Check -->
<td><?php echo $datum['task'];?></td>
<td><?php echo $datum['desc'];?></td>
<td><?php echo $datum['commission'];?></td>
<td><?php echo $datum['task_start'];?></td>
<td><?php echo $datum['task_end'];?></td>
</tr>
<!-- Remember Last Condition -->
<?php $the_project = $datum['project'];?>
<?php }?>
<!-- /Main Loop -->
</tbody>
</table>
您不必比较所有Project
, Client
, Start Date
和End Date
,假设同一项目将具有相同的Client
, Start Date
和End Date
。 这就是为什么它只比较项目( $the_project
)。
数据
您可以将此作为样本数据使用,就像查询中的数据一样。
<?php
$data = array(
array(
"project" => "Mobile App",
"client" => "Client One",
"proj_start"=> "12-12-2017",
"proj_end" => "12-12-2019",
"task" => "task 1",
"desc" => "desc 1",
"commission"=> "1000",
"task_start"=> "01-01-2018",
"task_end" => "10-01-2018"
),
array(
"project" => "Mobile App",
"client" => "Client One",
"proj_start"=> "12-12-2017",
"proj_end" => "12-12-2019",
"task" => "task 2",
"desc" => "desc 2",
"commission"=> "1000",
"task_start"=> "01-02-2018",
"task_end" => "10-02-2018"
),
array(
"project" => "Mobile App",
"client" => "Client One",
"proj_start"=> "12-12-2017",
"proj_end" => "12-12-2019",
"task" => "task 3",
"desc" => "desc 3",
"commission"=> "1000",
"task_start"=> "01-04-2018",
"task_end" => "10-05-2018"
),
array(
"project" => "Web App",
"client" => "Client Two",
"proj_start"=> "12-12-2017",
"proj_end" => "12-12-2019",
"task" => "task 1",
"desc" => "desc 1",
"commission"=> "1000",
"task_start"=> "01-01-2018",
"task_end" => "10-01-2018"
),
array(
"project" => "Web App",
"client" => "Client Two",
"proj_start"=> "12-12-2017",
"proj_end" => "12-12-2019",
"task" => "task 2",
"desc" => "desc 2",
"commission"=> "1000",
"task_start"=> "01-02-2018",
"task_end" => "10-02-2018"
)
);
?>
提示1
我认为不再需要$i
,因为您可以从代码示例中的$key
获得相同的结果。 唯一的区别是$key
从0开始。
提示2
如果您仍然需要$i
,则可以简化此代码
<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
成
<tr class="<?php echo ($i%2==0) ? "even":"odd" ?>">
提示3
我不知道你的<tr>
偶数或奇数类的目的,但如果你想为每个类设计不同的颜色,你可能想检查Bootstrap并将其设置为<table class="table table-striped">
编辑查询为SELECT * FROM expenses, income WHERE expenses.projectname=income.projectname AND expenses.task=income.task Blockquote GROUP BY PROJECTID
首先,您应该重新安排$ viewdata1数据结构。 基本上,在主项目数据字段和任务数据字段之间分开,然后以更好的方式组合它们。
我的假设是:
1. [task,ExpenseName,ExpenseAmount,pn,cname,taskcost,amount,datetimepicker_mask] =>都是任务数据字段
2. [projectname,employee] =>是所有项目数据字段
在你的模型中 (让我们将它命名为project_model ),
1.具有仅查询[projectname或employee或projectID或所有其他项目数据字段]的函数 ,让我们将其命名为allProject() 。 确保它返回类似的东西
[
0 => [
'id' => 101,
'projectName' => 'Desktop App' ,
other project data fields
] ,
1 => [
'id' => 102,
'projectName' => 'Mobile App' ,
other project data fields
] ,
2 => [
'id' => 103,
'projectName' => 'Andriod App' ,
other project data fields
] ,
etc...
]
2.具有基于[projectname或projectID]搜索/查询[task,ExpenseName,ExpenseAmount,pn,cname,taskcost,amount,datetimepicker_mask]的函数...让我们将其命名为task_query(projectID) ...确保它返回类似的东西
[
0 => [
'id' => 222,
'projectID' => 101
'task' => 'task 1',
'description' => 'description 1',
other task data fields
] ,
1 => [
'id' => 236,
'projectID' => 101
'task' => 'task 2',
'description' => 'description 2',
other task data fields
] ,
2 => [
'id' => 245,
'projectID' => 101
'task' => 'task 3',
'description' => 'description 3',
other task data fields
] ,
etc.
]
在控制器中 ,
$data['viewdata1'] = $this->project_model->allProject();
foreach($data['viewdata1'] as $key => $value)
{
$value['taskData'] = $this->project_model->task_query($value['id']);
}
$ data ['viewdata1']应该看起来像......
[
0 => [
'id' => 101,
'projectName' => 'Desktop App' ,
other project data fields,
'taskData' => [
0 => [
'id' => 222,
'projectID' => 101,
'task' => 'task 1',
'description' => 'description 1',
other task data fields
] ,
1 => [
'id' => 236,
'projectID' => 101,
'task' => 'task 2',
'description' => 'description 2',
other task data fields
] ,
2 => [
'id' => 245,
'projectID' => 101,
'task' => 'task 3',
'description' => 'description 3',
other task data fields
] ,
etc.
]
] ,
1 => [
'id' => 102,
'projectName' => 'Mobile App' ,
other project data fields,
'taskData' => [
0 => [
'id' => 123,
'projectID' => 102,
'task' => 'task 1b',
'description' => 'description 1b',
other task data fields
] ,
1 => [
'id' => 124,
'projectID' => 102,
'task' => 'task 2b',
'description' => 'description 2b',
other task data fields
] ,
2 => [
'id' => 125,
'projectID' => 102,
'task' => 'task 3b',
'description' => 'description 3b',
other task data fields
] ,
etc.
]
] ,
2 => [
'id' => 103,
'projectName' => 'Andriod App' ,
other project data fields,
'taskData' => [
0 => [
'id' => 567,
'projectID' => 103,
'task' => 'task 1c',
'description' => 'description 1c',
other task data fields
] ,
1 => [
'id' => 568,
'projectID' => 103,
'task' => 'task 2c',
'description' => 'description 2c',
other task data fields
] ,
2 => [
'id' => 569,
'projectID' => 103,
'task' => 'task 3c',
'description' => 'description 3c',
other task data fields
] ,
etc.
]
] ,
etc...
]
你们都为观点做好了准备
<table class="table table-lg">
<thead >
<tr class="filters">
<th><input type="text" class="form-control" placeholder="Project" disabled></th>
<th><input type="text" class="form-control" placeholder="Employee" disabled></th>
<th><input type="text" class="form-control" placeholder="Task" disabled></th>
<th><input type="text" class="form-control" placeholder="Expense" disabled></th>
<th><input type="text" class="form-control" placeholder="Amount" disabled></th>
<th><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
<th><input type="text" class="form-control" placeholder="Client" disabled></th>
<th><input type="text" class="form-control" placeholder="Cost" disabled></th>
<th><input type="text" class="form-control" placeholder="Income " disabled></th>
<th><input type="text" class="form-control" placeholder="Date" disabled></th>
</tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
foreach ($view_data1 as $key1 => $data1) {
$howManyTasks = count($data1['taskData']);
?>
<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
<td rowspan="<?= $howManyTasks ?>"><?php echo $data1['projectname']; ?></td>
<td rowspan="<?= $howManyTasks ?>"><?php echo $data1['employee']; ?></td>
<?php foreach($data1['taskData'] as $key2 => $data2) {?>
<td><?php echo $data2['task']; ?></td>
<td><?php echo $data2['ExpenseName']; ?></td>
<td><?php echo $data2['ExpenseAmount']; ?></td>
<td><?php echo $data2['pn']; ?></td>
<td><?php echo $data2['cname']; ?></td>
<td><?php echo $data2['taskcost']; ?></td>
<td><?php echo $data2['amount']; ?></td>
<td><?php echo $data2['datetimepicker_mask']; ?></td>
</tr>
<?php if($key2 != ($howManyTasks-1) ){ ?> <tr> <?php } ?>
<?php } ?>
<?php
$i++;
}
else:
?>
<tr>
<td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
endif;
?>
</tbody>
</table>
if($key == 0){
$project_name = $data['projectname'];
$first = true;
}else{
$first = false;
if($project_name != $data['projectname']){
$project_name = $data['projectname'];
$first = true;
}
}
<td><?php
if($first == true){
ehco $data['projectname'];
}else{
echo "";
}
</td>
在你的foreach中尝试这样的我没有厌倦但它可能有用,你可能会得到一些想法。 在第一个循环中,它将检查$ key,首先它将为0,如果$ key不为0,则$ first变量将为true然后它将检查$ project name到循环项目名称,如果它不匹配则将替换它。 对要删除或清空的客户端和其他列使用相同的列表。 我希望这可行或者它会给你一些想法。
使用in_array()
函数并为你的td
设置你的colspan
和rowspan
在您的视图页面中使用以下代码,
<table class="table table-lg">
<thead >
<tr class="filters">
<th><input type="text" class="form-control" placeholder="Project" disabled></th>
<th><input type="text" class="form-control" placeholder="Employee" disabled></th>
<th><input type="text" class="form-control" placeholder="Task" disabled></th>
<th><input type="text" class="form-control" placeholder="Expense" disabled></th>
<th><input type="text" class="form-control" placeholder="Amount" disabled></th>
<th><input type="text" class="form-control" placeholder="Paid/Not" disabled></th>
<th><input type="text" class="form-control" placeholder="Client" disabled></th>
<th><input type="text" class="form-control" placeholder="Cost" disabled></th>
<th><input type="text" class="form-control" placeholder="Income " disabled></th>
<th><input type="text" class="form-control" placeholder="Date" disabled></th>
</tr>
</thead>
<tbody>
<?php
if(isset($view_data1) && is_array($view_data1) && count($view_data1)): $i=1;
foreach ($view_data1 as $key => $data)
{
$number_of_task[$data['projectname']][] = $data['task'];
}
foreach ($view_data1 as $key => $data) {
$array = array();
?>
<tr <?php if($i%2==0){echo 'class="even"';}else{echo'class="odd"';}?>>
<?php if(!in_array($data['projectname'],$array)) {
$array[] = $data['projectname'];
?>
<td><?php echo $data['projectname']; ?></td>
<td><?php echo $data['employee']; ?></td>
<?php } else { ?>
<td colspan="2" rowspan="<?php echo count($number_of_task[$data['projectname']]); ?>"> </td>
<td><?php echo $data['task']; ?></td>
<td><?php echo $data['ExpenseName']; ?></td>
<td><?php echo $data['ExpenseAmount']; ?></td>
<td><?php echo $data['pn']; ?></td>
<td><?php echo $data['cname']; ?></td>
<td><?php echo $data['taskcost']; ?></td>
<td><?php echo $data['amount']; ?></td>
<td><?php echo $data['datetimepicker_mask']; ?></td>
</tr>
<?php
$i++;
}
}
else:
?>
<tr>
<td colspan="7" align="center" >No Records Found..</td>
</tr>
<?php
endif;
?>
</tbody>
</table>
这是我处理它的方式。 我希望这和你遇到的问题一样:)
*重要的是,变量$ dcost和$ cd是我自己设置的变量,请根据你的需要进行调整
foreach(your sql variable){
echo '<tr><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['destination'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timeout'].'</td>';
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="mday">'.$cd['mday'].'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" data-mrate="'.$cd['mrate'].'" class="mrate">'.rupiah($cd['mrate']).'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="tm"></td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="lday">'.$cd['lday'].'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" data-lrate="'.$cd['lrate'].'" class="lrate">'.rupiah($cd['lrate']).'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="tl"></td></tr>';}
代码之后
foreach(your sql variable){
echo '<tr>';
if($i - 1 == 1){
$i = 0;
echo ' <td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['destination'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timein'].'</td>
<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;">'.$dcost['timeout'].'</td>';
}else{
echo ' <td colspan="5" style="border-right:1px solid #000;"> </td>';
}
echo '<td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="mday">'.$cd['mday'].'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" data-mrate="'.$cd['mrate'].'" class="mrate">'.rupiah($cd['mrate']).'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="tm"></td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="lday">'.$cd['lday'].'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" data-lrate="'.$cd['lrate'].'" class="lrate">'.rupiah($cd['lrate']).'</td><td style="border-right:1px solid #000;text-align:center;vertical-align:middle;" class="tl"></td></tr>';}
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