DataWeave 函数

Question

这是我的 JSON 请求，我想从 DataWeave 转换中的 JSON 负载中删除dcsId字段。

我该怎么做？

{
    "status": "ok",
    "statusCode": "11011",
    "statusDescription": "Service: Get Profile ; Market: US ; Locale:en-US ; SourceId:DCS; ApiUid: 644e1dd7-2a7f-18fb-b8ed-ed78c3f92c2b; Description: The get profile call was successful.",
    "details": {
        "dcsId": "rfggrg",
        "marketCode": "US",
        "languageCode": "en",
        "profile": {
            "base": {
                "username": "abc",
                "firstName": "xc",
                "middleName": "test",
                "lastName": "123",
                "shortName": "xc",
                "displayName": "D",
                "suffix": "T",
                "prefix": "E"
            }
        }
    }
}

Answer 1

为了避免在有效负载中映射其他字段，您可以尝试这个 -

%dw 1.0
%output application/json
---
(payload - 'details') ++ (payload.details - 'dcsId')

它首先获取有效负载中除详细信息之外的所有内容，然后通过排除 dcsId 添加详细信息。

哼！

Answer 2

试试这个

%dw 1.0
%output application/json
---
{
    status : payload.status,
    statusCode : payload.status,
    statusDescription : payload.statusDescription,
    details :  payload.details - 'dcsId' 
}

希望这会有所帮助。

Answer 3

这是刚刚删除 dcsId 的表达式

    (payload - 'details') ++ {details: payload.details - 'dcsId'}

Answer 4

试试这个。

%dw 1.0
%output application/json
---
(payload - 'details') 
++ 
details:(payload.details - 'dcsId')

Answer 5

脚本

%dw 2.0
output application/json
---
    (payload - 'details') ++ {details: payload.details - 'dcsId'}

输出

{
  "status": "ok",
  "statusCode": "11011",
  "statusDescription": "Service: Get Profile ; Market: US ; Locale:en-US ; SourceId:DCS; ApiUid: 644e1dd7-2a7f-18fb-b8ed-ed78c3f92c2b; Description: The get profile call was successful.",
  "details": {
    "marketCode": "US",
    "languageCode": "en",
    "profile": {
      "base": {
        "username": "abc",
        "firstName": "xc",
        "middleName": "test",
        "lastName": "123",
        "shortName": "xc",
        "displayName": "D",
        "suffix": "T",
        "prefix": "E"
      }
    }
  }
}

Answer 6

这是一个递归函数，用于从任何级别的 json 有效负载中删除密钥

%dw 2.0
output application/json
var data = {
    "status": "ok",
    "statusCode": "11011",
    "statusDescription": "Service: Get Profile ; Market: US ; Locale:en-US ; SourceId:DCS; ApiUid: 644e1dd7-2a7f-18fb-b8ed-ed78c3f92c2b; Description: The get profile call was successful.",
    "details": {
        "dcsId": "rfggrg",
        "marketCode": "US",
        "languageCode": "en",
        "profile": {
            "base": {
                "username": "abc",
                "firstName": "xc",
                "middleName": "test",
                "lastName": "123",
                "shortName": "xc",
                "displayName": "D",
                "suffix": "T",
                "prefix": "E"
            }
        }
    }
}

fun removeKey(val, keyToRemove) = val match {
    case is Array -> $ map ((v) -> removeKey(v, keyToRemove))
    case is Object -> ($ - keyToRemove) mapObject ((value, key, index) -> {(key): removeKey(value,keyToRemove)})
    else -> $
  }
---
removeKey(data,"dcsId")