[英]HTTP Status 400 - Required String parameter 'xx' is not present
[英]HTTP Status 400 - Required String parameter 'walletName' is not present
我使用Java/ Spring MVC RESTful
应用程序并在执行POST
请求时收到400 HTTP status error
。 提供了@RestController
方法,
@RequestMapping(value = "/generateAddress", method = RequestMethod.POST)
public ResponseEntity<WalletInfoWrapper> generateAddress(@RequestParam("walletName") String walletName,
@RequestParam("currencyName") String currencyName) {
logger.info("walletName {} and currencyName {}", walletName, currencyName);
// return if the wallet name or the currency is null
if (Objects.isNull(walletName) || Objects.isNull(currencyName)) {
return new ResponseEntity<WalletInfoWrapper>(HttpStatus.NOT_ACCEPTABLE);
}
WalletInfo walletInfo = walletService.generateAddress(walletName, currencyName);
if (Objects.isNull(walletInfo)) {
return new ResponseEntity<WalletInfoWrapper>(HttpStatus.NOT_ACCEPTABLE);
}
WalletInfoWrapper walletInfoWrapper = new WalletInfoWrapper();
walletInfoWrapper.setName(walletInfo.getName());
return new ResponseEntity<WalletInfoWrapper>(walletInfoWrapper, HttpStatus.CREATED);
}
下面提供的Postman
的POST
请求,
错误消息通知, Required String parameter 'walletName' is not present
我还可以提供用于观察下拉操作的services
和dataase
层的代码。 这里有什么问题?
UPDATE
我像这样更新了Postman
请求,但仍然出现相同的错误,
UPDATE 1
我还是有同样的问题
我用数据POST
,
{"walletName":"puut","currencyName":"Bitcoin"}
下面提供了代码,
@RequestMapping(value = "/generateAddress", method = RequestMethod.POST, produces = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<WalletInfoWrapper> generateAddress(@RequestBody WalletWithMoneyRequest walletWithMoneyRequest) {
String walletName = walletWithMoneyRequest.getWalletName();
String currencyName = walletWithMoneyRequest.getCurrencyName();
logger.info("walletName {} and currencyName {}", walletName, currencyName);
// return if the wallet name or the currency is null
if (Objects.isNull(walletName) || Objects.isNull(currencyName)) {
return new ResponseEntity<WalletInfoWrapper>(HttpStatus.NOT_ACCEPTABLE);
}
WalletInfo walletInfo = walletService.generateAddress(walletName, currencyName);
if (Objects.isNull(walletInfo)) {
return new ResponseEntity<WalletInfoWrapper>(HttpStatus.NOT_ACCEPTABLE);
}
WalletInfoWrapper walletInfoWrapper = new WalletInfoWrapper();
walletInfoWrapper.setName(walletInfo.getName());
return new ResponseEntity<WalletInfoWrapper>(walletInfoWrapper, HttpStatus.CREATED);
}
提供了POJO
,
private class WalletWithMoneyRequest {
String walletName;
String currencyName;
public WalletWithMoneyRequest(String walletName, String currencyName) {
this.walletName = walletName;
this.currencyName = currencyName;
}
public WalletWithMoneyRequest() {
}
public String getWalletName() {
return walletName;
}
public String getCurrencyName() {
return currencyName;
}
public void setCurrencyName(String currencyName) {
this.currencyName = currencyName;
}
public void setWalletName(String walletName) {
this.walletName = walletName;
}
}
这是错误信息,
这里是Tomcat服务器信息,
org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver: 08/19/2017 19:45:55 - Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot construct instance of `mobi.puut.controllers.WalletRestController$WalletWithMoneyRequest` (although at least one Creator exists): can only instantiate non-static inner class by using default, no-argument constructor; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot construct instance of `mobi.puut.controllers.WalletRestController$WalletWithMoneyRequest` (although at least one Creator exists): can only instantiate non-static inner class by using default, no-argument constructor
at [Source: (PushbackInputStream); line: 1, column: 2]
Tomcat Localhost log
您的控制器需要 2 个通常如下所示的请求参数:/someurl?walletName=my-wallets-name¤cyName=dollars。
您在帖子正文中发送一个 json 字符串,但没有形式参数。 您需要更新您的 POST 或您的控制器以使两端一致。 我认为您可能想用一个 Java pojo 替换两个带 @RequestParam 注释的字符串,该 Java pojo 具有两个字符串成员:walletName 和 currencyName,将该 pojo 作为参数放入您的请求方法中,并在其前面加上注释 @RequestBody。 这将匹配您的 json 帖子。
要让您的控制器接受正文中带有 JSON 的帖子,请像这样编辑它:
@RequestMapping(value = "/generateAddress", method = RequestMethod.POST)
public ResponseEntity<WalletInfoWrapper> generateAddress(@RequestBody
WalletWithMoneyRequest myJsonRequestComingIn) {
logger.info("walletName {} and currencyName {}", myJsonRequestComingIn.getWalletName(), myJsonRequestComingIn.getCurrencyName());
还有你的 pojo
public class WalletWithMoneyRequest{
private String walletName;
private String currencyName;
//getters and setters down here.
详细说明 zerpsed 的回答。
将签名更改为:
public ResponseEntity<WalletInfoWrapper> generateAddress(@ResponseBody WalletPOJO walletCurrency)
WalletPOJO 有两个字段 walletName 和 currencyName
我相信这个问题现在已经解决了。 我按照RESTful
方法中的@RequestBody
参数的建议使用了POJO
。 这里的问题是我需要将POJO
从类中取出(尽管在同一个文件中),然后将其作为实体放入实体目录中。
class WalletWithMoneyRequest {
String walletName;
String currencyName;
public WalletWithMoneyRequest(String walletName, String currencyName) {
this.walletName = walletName;
this.currencyName = currencyName;
}
public WalletWithMoneyRequest() {
}
public String getWalletName() {
return walletName;
}
public String getCurrencyName() {
return currencyName;
}
public void setCurrencyName(String currencyName) {
this.currencyName = currencyName;
}
public void setWalletName(String walletName) {
this.walletName = walletName;
}
}
主要问题是相信是HQL
的错误,
我写了currency =: currency
,它应该是currency = :currency
我仍然无法在数据库中拥有数据,因为我需要修改database
层中的方法。
En POSTMAN 在 params 中设置变量
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