[英]Radio button show text
我想问....为什么我的下拉菜单不显示文字? 我确保我的代码是正确的....但是我什么都不能显示文本.....我对此感到非常困惑...这是我的单选按钮图片:
这是我在view.php中的html代码.........
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div class="dropdown dropdown-full-width dropdown-category">
<button class="btn btn-default dropdown-toggle" type="button" data-toggle="dropdown" >
<span class="name">
<span id="category-select">- -
@foreach($categoriesid as $kategori)
{{ $kategori->name}} -
@endforeach
-</span>
</span>
<span class="caret"></span>
</button>
<div class="dropdown-menu row">
<div class="col-md-4">
<li><strong>By {{ $category[1] }}</strong></li>
@foreach($category1 as $occasions)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $occasions->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['occasions']" class="category-radio" value="{{ $occasions->id }}" checked="checked"> {{ $occasions->name }}</label>
@else
<label><input type="radio" name="category['occasions']" class="category-radio" value="{{ $occasions->id }}"> {{ $occasions->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
<div class="col-md-4">
<li><strong>By {{ $category[2] }}</strong></li>
@foreach($category2 as $types)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $types->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['types']" class="category-radio" value="{{ $types->id }}" checked="checked"> {{ $types->name }}</label>
@else
<label><input type="radio" name="category['types']" class="category-radio" value="{{ $types->id }}"> {{ $types->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
<div class="col-md-4">
<li><strong>By {{ $category[3] }}</strong></li>
@foreach($category3 as $flowers)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $flowers->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['flowers']" class="category-radio" value="{{ $flowers->id }}" checked="checked"> {{ $flowers->name }}</label>
@else
<label><input type="radio" name="category['flowers']" class="category-radio" value="{{ $flowers->id }}"> {{ $flowers->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
</div>
</div>
这是我的JavaScript代码。
$(function(){
$('input[type="radio"]').click(function(){
var $radio = $(this);
var name = $(this).prop("name");
// if else for checked true and false
if ($radio.data('waschecked') == true)
{
$radio.prop('checked', false);
$radio.data('waschecked', false);
$('#category-select').text('');
}
else{
$radio.data('waschecked', true);
$(`input[name=${name}]:not(:checked)`).data('waschecked', false);
$('#category-select').text(txt).trim();
}
let output = [];
var txt;
$('input[type="radio"]:checked').each( function() {
txt = $(this).parent().text().trim();
output.push(txt);
});
$('#category-select').text(output.join(' - '));
});
});
请帮助我有关此javascript ...因为我是javascript的新手.....
我得到答案了。
$('.dropdown-menu').on('click', function(e) { e.stopPropagation(); }); $(function(){ var $radio = $(this); if($('input[type="radio"]:checked').data('waschecked', true)) { $radio.data('waschecked', true); } $('input[type="radio"]').click(function(){ var $radio = $(this); var name = $(this).prop("name"); // if else for checked true and false if ($radio.data('waschecked') == true) { $radio.prop('checked', false); $radio.data('waschecked', false); $('#category-select').text(''); } else{ $radio.data('waschecked', true); $('input[type="radio"]:not(:checked)').data('waschecked', false); $('#category-select').text(txt); } let output = []; var txt; $('input[type="radio"]:checked').each( function() { txt = $(this).parent().text(); output.push(txt); }); $('#category-select').text(output.join(' - ')); }); });
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.