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[英]Ambiguous overload of std::ostream& operator<<(std::ostream& sstr, const T& val)
[英]'operator<<(std::ostream&, int&)’ is ambiguous
这不是吗?
operator<<(std::cout, 0);
一样吗
std::cout<<0;
我尝试了这段代码:
#include<iostream>
int main()
{
operator<<(std::cout,0);
return 0;
}
但是我收到以下错误消息:
a.cpp: In function ‘int main()’:
a.cpp:11:28: error: call of overloaded ‘operator<<(std::ostream&, int)’ is ambiguous
a.cpp:11:28: note: candidates are:
/usr/include/c++/4.6/ostream:528:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, const unsigned char*) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:523:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, const signed char*) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:510:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, const char*) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/bits/ostream.tcc:323:5: note: std::basic_ostream<_CharT, _Traits>& std::operator<<(std::basic_ostream<_CharT, _Traits>&, const char*) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:473:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, unsigned char) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:468:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, signed char) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:462:5: note: std::basic_ostream<char, _Traits>& std::operator<<(std::basic_ostream<char, _Traits>&, char) [with _Traits = std::char_traits<char>]
/usr/include/c++/4.6/ostream:456:5: note: std::basic_ostream<_CharT, _Traits>& std::operator<<(std::basic_ostream<_CharT, _Traits>&, char) [with _CharT = char, _Traits = std::char_traits<char>]
有人可以解释吗?
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