Ajax表单发布仅适用于Firefox

Question

我有一个Ajax登录表单，但仅在Firefox上能很好地工作。 在其他浏览器上，它会继续发布表单并加载功能页面。 我希望它将2个字段发布到功能页面，并进行后台处理检查，并将其写入loginform.html中的#resultgiris标记。

loginform.html

<form id="girisformu" action="fonksiyon/loginkontrol.php" onsubmit="return false;" data-parsley-validate class="form-horizontal form-label-left" >
                      <div class="form-group">
                        <div class="col-md-12 col-sm-12 col-xs-12">
                          <input type="text" id="user_id" name="user_id" class="form-control has-feedback-left" data-inputmask="'mask' : '99999999999'" placeholder="Kullanıcı ID">
                          <span class="fa fa-user form-control-feedback left" aria-hidden="true"></span>
                        </div>
                      </div>
                      <div class="form-group">
                        <div class="col-md-12 col-sm-12 col-xs-12">
                          <input type="password" name="password_giris" id="password_giris" class="form-control has-feedback-left" placeholder="Şifre">
                          <span class="fa fa-key form-control-feedback left" aria-hidden="true"></span>
                        </div>
                      </div>
                      <div class="form-group">
                      <div class="col-md-12 col-sm-12 col-xs-12 pull-right">
                      <center><h5><a href="#kayitOl" data-toggle="modal" data-target="#kayitOl"><span class="fa fa-user-plus" aria-hidden="true"></span> Kayıt Ol</a>   -   <a href="#sifremiUnuttum" data-toggle="modal" data-target="#sifremiUnuttum"><span class="fa fa-question-circle" aria-hidden="true"></span> Şifremi Unuttum</a></h5></center>
                        </div><div class="col-md-12 col-sm-12 col-xs-12 pull-right">
                     <center><button type="reset" class="btn btn-primary"><span class="fa fa-trash" aria-hidden="true"></span> Temizle</button>
                          <button id="girisbtn" class="btn btn-success"><span class="fa fa-sign-in" aria-hidden="true"></span> Giriş Yap</button></center>
                              </div>
                               </div>
                      </form>

loginkontrol.php（功能页）

<?php
include_once('../inc/database.php');
        $userid = $_POST['user_id'];
        $password = $_POST['password_giris'];

        $result = mysqli_query($baglan, "SELECT `userid`,`sifre`
            FROM `uye` WHERE `userid` = '$userid' AND `sifre` = '$password'") or die (mysqli_error($baglan));
        $row = mysqli_fetch_assoc($result);
        if(mysqli_num_rows($result) <= 0){
            echo "Login failed";
            else{
                echo "Successful login";
            }
?>

login.js

$("#girisbtn").click( function() {
    document.getElementById("loadinggiris").style.display = 'inline';
 $.post( $("#girisformu").attr("action"), 
         $("#girisformu :input").serializeArray(), 
         function(info){ $("#resultgiris").html(info); 
   });

});

$("#girisformu").submit( function() {
    event.preventDefault();

});

function clearInput() {

    $("#girisformu :input").each( function() {
       $(this).val('');
    });


}

Answer 1

感谢@Cbroe的评论，我解决了我的问题。 我定义了一个函数；

<script>
function engelle(e){

e.preventDefault();

}
</script>

然后将登录按钮的onclick更改为'onclick =“ engelle（event）”'