![](/img/trans.png)
[英]JVM does not respond when user clicks button 1/2, it just becomes stuck
[英]Show dialog when user becomes offline and dismiss it when user becomes online (with broadcastReceiver)
这是我的基本活动,是课堂activity
扩展。 我让我的其他活动扩展了这个基类:
public abstract class Base extends Activity {
private BroadcastReceiver netStateReceiver;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(getLayoutResourceId());
}
protected abstract int getLayoutResourceId();
@Override
protected void onPause() {
if (netStateReceiver != null) {
unregisterReceiver(netStateReceiver);
netStateReceiver = null;
}
super.onPause();
}
@Override
protected void onResume() {
if (netStateReceiver == null) {
netStateReceiver = new BroadcastReceiver() {
@Override
public void onReceive(final Context context, Intent intent) {
final Dialog offline = new Dialog(context, android.R.style.Theme_Light);
//A change occurred in connection state. Check whether user has been become online or offline:
if (!CheckNet()) {
//User became offline (show offline dialog):
offline.setContentView(R.layout.activity_offline);
offline.setTitle("offline");
offline.getWindow().setBackgroundDrawableResource(R.color.transparent);
offline.show();
final Button retry = (Button) offline.findViewById(R.id.button6);
retry.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (CheckNet()) {
offline.dismiss();
}
}
});
}
else {
//User became online (dismiss offline dialog):
if (offline.isShowing()) {
offline.dismiss();
}
}
}
};
registerReceiver(netStateReceiver, new IntentFilter(Values.CONNECTIVITY_RECEIVER_ACTION));
}
super.onResume();
}
private boolean CheckNet() {
final ConnectivityManager conMgr = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
final NetworkInfo activeNetwork = conMgr.getActiveNetworkInfo();
return (activeNetwork != null && activeNetwork.isConnectedOrConnecting());
}
}
如您在代码中看到的,我已经注册了一个用于检查连接状态的接收器。
我希望当用户脱机时向用户显示一个对话框,并通知他他已脱机,应该联机后才能继续。 这部分效果很好。
我还希望在显示该对话框时以及在用户联机时将此对话框关闭,但是该部分不起作用并且对话框仍保留在显示屏上。
有什么问题,如何关闭对话框?
您可以在每个广播上创建一个新对话框,而不使用以前已经创建的对话框。
使对话框变量成为活动类的成员变量,然后它将起作用。
private Dialog offline;
@Override
protected void onResume() {
if (netStateReceiver == null) {
netStateReceiver = new BroadcastReceiver() {
@Override
public void onReceive(final Context context, Intent intent) {
if (!CheckNet()) {
if(offline==null || !offline.isShowing()){
offline = new Dialog(context, android.R.style.Theme_Light);
}
...
} else {
//User became online (dismiss offline dialog):
if (offline!=null && offline.isShowing()) {
offline.dismiss();
}
}
每次接收广播时,您都在创建一个新对话框,因此您关闭的对话框与用于显示“您当前处于离线状态”的对话框完全不同。
尝试将“离线”对话框放在活动中,而不是放在onReceive回调中。
一个简单的例子是:
public abstract class Base extends Activity {
private BroadcastReceiver netStateReceiver;
final Dialog offline;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(getLayoutResourceId());
// You create the dialog here instead within the onReceive callback
offline = new Dialog(this, android.R.style.Theme_Light);
offline.setContentView(R.layout.activity_offline);
offline.setTitle("offline");
offline.getWindow().setBackgroundDrawableResource(R.color.transparent);
}
@Override
protected void onResume() {
if (netStateReceiver == null) {
netStateReceiver = new BroadcastReceiver() {
@Override
public void onReceive(final Context context, Intent intent) {
if (!CheckNet()) {
// Your dialog already exists, just show it immediately
offline.show();
final Button retry = (Button) offline.findViewById(R.id.button6);
retry.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if (CheckNet()) {
offline.dismiss();
}
}
});
}
else {
//User became online (dismiss offline dialog):
if (offline.isShowing()) {
offline.dismiss();
}
}
}
};
registerReceiver(netStateReceiver, new IntentFilter(Values.CONNECTIVITY_RECEIVER_ACTION));
}
super.onResume();
}
}
使它全局访问您的对话框对象引用:
final Dialog offline = new Dialog(context, android.R.style.Theme_Light);
然后,您将能够关闭对话框。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.