使用isset（$ _ POST ['name']）进行PHP表单验证

Question

Robin Nixon的书中的代码：

if (isset($_POST['user'])) {
  $user = sanitizeString($_POST['user']);
  $pass = sanitizeString($_POST['pass']);
  if ($user == "" || $pass == "")
    $error = "Not all fields were entered<br><br>";
  else {
    $result = queryMysql("SELECT * FROM members WHERE user='$user'");
    if ($result - > num_rows)
      $error = "That username already exists<br><br>";
    else {
      queryMysql("INSERT INTO members VALUES('$user', '$pass')");
      die("<h4>Account created</h4>Please Log in.<br><br>");
    }
  }
}

为什么他在这里使用isset（$ _ POST ['user']）？ 为什么他不使用isset（$ _ POST ['submit']代替？

Answer 1

准则已缺少结束括号。

<?php
if (isset($_POST['user']))
{
$user = sanitizeString($_POST['user']);
$pass = sanitizeString($_POST['pass']);
if ($user == "" || $pass == "")
$error = "Not all fields were entered<br><br>";
else
{
$result = queryMysql("SELECT * FROM members WHERE user='$user'");
if ($result->num_rows)
$error = "That username already exists<br><br>";
else
{
queryMysql("INSERT INTO members VALUES('$user', '$pass')");
die("<h4>Account created</h4>Please Log in.<br><br>");
 } 
}
}
?>

现在，如果设置了POST用户，该代码将接受。 或者如果在您的html表单字段上实现代码，则提交！ 如果您需要POST提交检查，那么..我想做什么？ 请告知我可以根据需要进行修改。