如何保持休眠状态下的外键关系

Question

我有两个类，并且我希望它们之间具有一对多的关系，例如：

Home(id<int>, rooms<string>)

Vehicle(id<int>, home_id<int>, name<string>) 

我需要之间的关系， Home和Vehicle使用类Home.id和vehicle.home_id 。

请提出我可以在此处用于CURD操作以实现REST服务的任何示例。

Answer 1

我需要之间的关系， Home和Vehicle使用类Home.id和vehicle.home_id 。

您的实体应如下所示：

车辆实体

@Entity
@Table(name = "vehicle", catalog = "bd_name", schema = "schema_name")
@XmlRootElement
public class Vehicle implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "id")
    private Integer id;
    @Column(name = "name")
    private String name;
    @JoinColumn(name = "home_id", referencedColumnName = "id")
    @ManyToOne
    private Home homeId;

    //constructor getter & setters

}

家庭实体

@Entity
@Table(name = "home", catalog = "bd_name", schema = "schema_name")
@XmlRootElement
public class Home implements Serializable {

    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "id")
    private Integer id;
    @Column(name = "room")
    private Character room;
    @OneToMany(mappedBy = "homeId")
    private List<Vehicle> vehicleList;

    //constructor getter & setters
}