![](/img/trans.png)
[英]How to write WHERE clause with a Datetime using Sequelize in Node
[英]How to write subquery with multiple where in sequelize using NodeJS
我需要使用sequelize执行此查询。
select * from mysqlDB.songTable where
X in (SELECT X FROM movieDB4.songTable where Y like('%pencil%') and Z='title') and
Y='tam' and Z='language';
我尝试过这样。 但是会引发一些无效的value [object]错误。 请帮助解决该查询。
const tempSQL = sequelize.dialect.QueryGenerator.selectQuery('songTable',{
attributes: ['X'],
where: {
Y: {$like: '%'+text[i]},
Z: "content_title"
}})
.slice(0,-1); // to remove the ';' from the end of the SQL
User.findAll({
where: {
X: {
$in: sequelize.literal('(' + tempSQL + ')'),
$and: {Y: lang.substring(0,3),
Z: 'language'}
}
}
})
您可以使用sequelize.query()执行原始查询。
例
return this.sequelize.query(`SELECT category_id, category_name from table_categories where category_id in (SELECT DISTINCT category_id from table_authorized_service_center_details where center_id in (SELECT center_id from table_authorized_service_center where brand_id ${condition}));`).then((results) => {
if (results.length === 0) {
reply({status: true, categories: [], forceUpdate: request.pre.forceUpdate});
} else {
reply({status: true, categories: results[0], forceUpdate: request.pre.forceUpdate});
}
}).catch((err) => {
console.log(err);
reply({status: false, message: "ISE"});
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.