[英]SQL returns duplicated values
我在使用SQL查询时遇到问题,因为它返回多行,我只想从中获取值
ps_tax t
有人可以帮助我吗?
SELECT bgc.id_product,bgc.id_order, tx.id_tax_rules_group,t.id_tax,pl.name,t.rate as rate, brl.price as gift_price
FROM ps_bestkit_gift_cart bgc
LEFT JOIN ps_bestkit_gift_rule brl ON brl.id_bestkit_gift_rule = bgc.id_bestkit_gift_rule
LEFT JOIN ps_product_lang pl ON bgc.id_product = pl.id_product
LEFT JOIN ps_product p ON pl.id_product = p.id_product
LEFT JOIN ps_tax_rule tx ON p.id_tax_rules_group = tx.id_tax_rules_group
LEFT JOIN ps_tax t ON tx.id_tax = t.id_tax
WHERE id_order =8452
AND pl.id_lang=3
AND tx.id_country=6
DDL
CREATE TABLE ps_bestkit_gift_rule ( id_bestkit_gift_rule int(11) unsigned NOT NULL AUTO_INCREMENT, is_product_depends tinyint(1) unsigned DEFAULT NULL, is_supplier_depends tinyint(1) unsigned DEFAULT NULL, is_manufacturer_depends tinyint(1) unsigned DEFAULT NULL, is_category_depends tinyint(1) unsigned DEFAULT NULL, is_attribute_depends tinyint(1) unsigned DEFAULT NULL, is_feature_depends tinyint(1) unsigned DEFAULT NULL, is_allow_other_gift tinyint(1) unsigned DEFAULT NULL, cart_amount decimal(17,2) unsigned NOT NULL, max_cart_amount decimal(17,2) unsigned NOT NULL, price decimal(17,2) unsigned NOT NULL, min_qty_inside_category int(10) unsigned NOT NULL DEFAULT 0, min_price_inside_category decimal(17,2) unsigned NOT NULL, from_date date NOT NULL, to_date date NOT NULL, criteria_order_type varchar(32) NOT NULL, criteria_max_per_customer int(11) unsigned NOT NULL, criteria_nb_products int(11) unsigned NOT NULL, gift_preselector_product_page tinyint(1) unsigned DEFAULT NULL, available_gifts int(10) unsigned NOT NULL DEFAULT 1, criteria_coupon text, criteria_customer_group text, message tinyint(1) unsigned DEFAULT NULL, active tinyint(1) unsigned DEFAULT NULL, position int(10) unsigned NOT NULL DEFAULT 0, PRIMARY KEY (id_bestkit_gift_rule) ) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=utf8
根据屏幕截图和您的评论,您只想从查询中删除两个值,即ID193(比率为21)和1539(比率为0),我想您要么是:
。
+------------+----------+--------------------+--------+--------+------------+
| ID_Product | ID_order | ID_TAX_RULES_GROUP | ID_TAX | Rate | Gift_price |
+------------+----------+--------------------+--------+--------+------------+
| 193 | 8452 | 4 | 4 | 21.000 | $5.00 |
| 1539 | 8452 | 4 | 4 | 21.000 | $- |
| 193 | 8452 | 4 | 7 | 0.000 | $5.00 |
| 1539 | 8452 | 4 | 7 | 0.000 | $- |
+------------+----------+--------------------+--------+--------+------------+
所以ID_TaX和Gift_price和rate都具有不同的值,毕竟我可能看错了表... gift_price的NULL可能是左连接的结果,这意味着ps_tax中ID_TAX和RATE的两个值可能是表有不正确的连接! 我来看看那张桌子上的PK / FK!
我认为GROUP BY可以胜任。
SELECT bgc.id_product,bgc.id_order,
tx.id_tax_rules_group,t.id_tax,pl.name,t.rate as rate, brl.price as gift_price
FROM ps_bestkit_gift_cart bgc
LEFT JOIN ps_bestkit_gift_rule brl ON brl.id_bestkit_gift_rule = bgc.id_bestkit_gift_rule
LEFT JOIN ps_product_lang pl ON bgc.id_product = pl.id_product
LEFT JOIN ps_product p ON pl.id_product = p.id_product
LEFT JOIN ps_tax_rule tx ON p.id_tax_rules_group = tx.id_tax_rules_group
LEFT JOIN ps_tax t ON tx.id_tax = t.id_tax
WHERE id_order =8452
AND pl.id_lang=3
AND tx.id_country=6
GROUP BY t.id_tax
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