[英]How can I send the image using Ajax
我想知道如何使用javascript ajax函数将图像数据发送到服务器(Django应用)。
以下是我的代码。
// Get filename of image
jsondata = JSON.parse(data);
image_file_name = jsondata.fileurl;
// document.getElementById('previewimage').src = image_file;
// I can show the image.
b64_image = btoa(unescape(encodeURIComponent(image_file)));
var credentials = {
filename: image_file_name,
image: b64_image,
};
// Send ajax request to the server
$.ajax({
url: HOST_NAME + "user/api/file_uploader/",
type: 'GET',
dataType: 'json',
data: credentials,
timeout: 10000,
})
.done(function (data) {
// Get the result
jsondata = JSON.parse(data);
alert("File upload completed...");
})
// If false...
.fail(function (XMLHttpRequest, textStatus, errorThrown) {
console.log("Upload error");
})
您必须使用FromData通过ajax发布文件。
var form = $('form')[0];
var formData = new FormData(form);
$.ajax({
url: "ajax_php_file.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
// success code .
}
});
您只需要在代码中进行一项更改。
// Send ajax request to the server
$.ajax({
url: HOST_NAME + "user/api/file_uploader/",
type: 'POST', // changed from GET to POST
dataType: 'json',
data: credentials,
timeout: 10000,
})
.done(function (data) {
// Get the result
})
.fail(function (XMLHttpRequest, textStatus, errorThrown) {
console.log("Upload error");
})
因为GET用于读取,而post用于创建。 您可以阅读有关请求方法的更多信息。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.