努力重组Json数据结构

Question

我正在尝试转换此JSON：

[
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 1
        },
        {
            "id": 3,
            "ac": 1
        }
    ],
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 1
        },
        {
            "id": 3,
            "ac": 0
        }
    ],
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 1
        },
        {
            "id": 3,
            "ac": 0
        }
    ],
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 0
        },
        {
            "id": 3,
            "ac": 0
        }
    ],
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 0
        },
        {
            "id": 3,
            "ac": 0
        }
    ],
    [
        {
            "id": 1,
            "ac": 1
        },
        {
            "id": 2,
            "ac": 0
        },
        {
            "id": 3,
            "ac": 0
        }
    ]
]

进入该数据结构：

[
    [
        {
            "id": 1,
            "ac": [1,1,1,1,1,1]
        }
    ],
    [
        {
            "id": 2,
            "ac": [1,1,1,0,0,0]
        }
    ],
    [
        {
            "id": 3,
            "ac": [1,0,0,0,0,0]
        }
    ]
]

我正在使用JavaScript /节点来执行此操作，但无法使其正常工作。 谁能帮我写一个可以做到的循环？

编辑：我尝试的是以下内容，但我想它并没有太大帮助，因为它仍然不是我需要的输出

var acc_array = [];
var a_id;
for(var y=0; y<data.length; y++) { //151
    if(y<data.length-1){
        a_id = data[y].a_id;
        if(a_id == data[y].a_id) {
            acc_array[y] = new Array();
            acc_array[y].push(data[y].acc);
        }
    }
    if(y==data.length-1){
        acc_array[y] = new Array();
        a_id = data[y].a_id;
        if(a_id == data[y].a_id) {
            acc_array[y].push(data[y].acc);
        }
        jsonfile.writeFile("a.json", acc_array, function (err) {
            console.log(err);
        });
    }
}

Answer 1

您可以采用嵌套循环和哈希表来收集具有相同id项目。

 var data = [[{ id: 1, ac: 1 }, { id: 2, ac: 1 }, { id: 3, ac: 1 }], [{ id: 1, ac: 1 }, { id: 2, ac: 1 }, { id: 3, ac: 0 }], [{ id: 1, ac: 1 }, { id: 2, ac: 1 }, { id: 3, ac: 0 }], [{ id: 1, ac: 1 }, { id: 2, ac: 0 }, { id: 3, ac: 0 }], [{ id: 1, ac: 1 }, { id: 2, ac: 0 }, { id: 3, ac: 0 }], [{ id: 1, ac: 1 }, { id: 2, ac: 0 }, { id: 3, ac: 0 }]], hash = Object.create(null), result = []; data.forEach(function (a) { a.forEach(function (o) { hash[o.id] || result.push(hash[o.id] = { id: o.id, ac: [] }); hash[o.id].ac.push(o.ac); }); }); console.log(result); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 2

Array＃将所有内容都组合到单个数组中，然后将Array＃reduce与帮助器对象一起使用以获取所需对象的数组：

 var data = [[{"id":1,"ac":1},{"id":2,"ac":1},{"id":3,"ac":1}],[{"id":1,"ac":1},{"id":2,"ac":1},{"id":3,"ac":0}],[{"id":1,"ac":1},{"id":2,"ac":1},{"id":3,"ac":0}],[{"id":1,"ac":1},{"id":2,"ac":0},{"id":3,"ac":0}],[{"id":1,"ac":1},{"id":2,"ac":0},{"id":3,"ac":0}],[{"id":1,"ac":1},{"id":2,"ac":0},{"id":3,"ac":0}]]; var hash = Object.create(null); var result = [].concat(...data) .reduce(function(r, o) { var item = hash[o.id]; if(!item) { item = hash[o.id] = { id: o.id, ac: [] }; r.push(item); } item.ac.push(o.ac); return r; }, []); console.log(result);