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SQL 选择来自同一列的多个计数

[英]SQL select with multiple counts from the same column

我在 SQL 中有一个表,其中包含以下列:状态、创建日期时间和案例类型

10 行数据的示例如下所示:

    Resolved-Withdrawn  2017-08-28 10:20:58.820 Termination Quote DE
    Pending-Customer    2017-08-28 10:44:37.987 Termination Quote DE
    Pending-Customer    2017-08-28 10:44:39.953 Termination Quote DE 
    Pending-Customer    2017-08-28 10:51:55.643 Termination Quote DE
    Pending-Customer    2017-08-28 10:51:56.513 Termination Quote DE
    Pending-Customer    2017-08-28 10:54:20.160 Termination Quote DE
    Pending-Customer    2017-08-28 10:54:20.747 Termination Quote DE
    Pending-Customer    2017-09-10 06:12:52.113 Termination Quote DE
    Pending-Customer    2017-09-15 12:34:32.657 Termination Quote DE

我想实现以下目标:

    Status               Total_August     Total_September
    -----------------------------------------------------
    Resolved-Withdrawn   1                0
    Pending-Customer     6                2

我将如何在 SQL 中创建此查询?

我最初的想法是这样的(这显然行不通),但也许它可以让您更好地了解我作为非经验用户的思维过程。

    SELECT Status, COUNT(pxCreateDateTime) as Total_August, COUNT(pxCreateDateTime) as Total_September
    FROM ContractMgtWork
    WHERE  MONTH(pxCreateDateTime) = 8 and YEAR(pxCreateDateTime) = 2017 AND 
    CaseType = 'Amortization Schedule DE'
    GROUP BY Status 

count ,像许多其他聚合函数一样,跳过null s。 您可以通过使用您想要计算的任何内容计算case表达式来利用此属性:

SELECT   Status, 
         COUNT(CASE WHEN MONTH(pxCreateDateTime) = 8 THEN 1 END) AS Total_August,
         COUNT(CASE WHEN MONTH(pxCreateDateTime) = 9 THEN 1 END) AS Total_September
FROM     ContractMgtWork
WHERE    YEAR(pxCreateDateTime) = 2017 AND 
         CaseType = 'Amortization Schedule DE'
GROUP BY Status 

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