PHP 循环遍历 JSON 响应并插入 MySQL

Question

对于学校项目，我想遍历 JSON 响应并将数据插入 MySQL 数据库。

JSON 响应如下所示：

{"tableID":100965,"data":[{"updated_at":1506994152000,"prices":{"unstable_reason":"LOW_SALES","unstable":true,"sold":{"avg_daily_volume":null,"last_90d":67,"last_30d":52,"last_7d":15,"last_24h":1},"max":287.5,"avg":93.52,"min":51.01,"latest":87},"image":"IMGURL","db_name":"Test-Artikel","dbID":"123456789"},{"updated_at":1506994152000,"prices":{"unstable_reason":"LOW_SALES","unstable":true,"sold":{"avg_daily_volume":null,"last_90d":67,"last_30d":52,"last_7d":15,"last_24h":1},"max":287.5,"avg":93.52,"min":51.01,"latest":87},"image":"IMGURL","db_name":"Test-Artikel","dbID":"123456789"}],"__v":0,"createdAt":"2017-03-27T09:16:48.395Z"}

每个数组都应该是 mysql 数据库中自己的一行。

目前，我可以使用以下代码从 json 文件中获取一个信息：

<?php
$url = "linktojson";

//connect to database
//$pdo = new PDO('mysql:host=localhost;dbname=...', '...', '...');

//read the json file contents
$jsondata = file_get_contents($url);

//convert json object to php associative array
$data = json_decode($jsondata, true);   

echo('<pre>');
foreach ($data['data'] as $api_data) {
    echo $api_data['name'] . '<br/>';

}
?>

编辑：当前代码：

$pdo = new PDO('mysql:host=localhost;dbname=XXX', 'XXX', 'XXX');
$yourJsonArray ="test.json";
$dataArray = json_decode(json_encode($yourJsonArray),true);
foreach($dataArray as $key => $value){
   $image = $key['image'];
   $statement = $pdo->prepare('INSERT INTO api_data (image) VALUES (?)'); 
   $statement->execute(array($image));
}

错误消息：警告：为第 29 行 test.php 中的 foreach() 提供的参数无效

第 29 行 = foreach（上面有一些旧评论）

编辑：添加var_dump($yourJsonArray); 在 foreach 之前：

string(638) "{"tableID":100965,"data":[{"updated_at":1506994152000,"prices":{"unstable_reason":"LOW_SALES","unstable":true,"sold":{"avg_daily_volume":null,"last_90d":67,"last_30d":52,"last_7d":15,"last_24h":1},"max":287.5,"avg":93.52,"min":51.01,"latest":87},"image":"IMGURL","db_name":"Test-Artikel","dbID":"123456789"},{"updated_at":1506994152000,"prices":{"unstable_reason":"LOW_SALES","unstable":true,"sold":{"avg_daily_volume":null,"last_90d":67,"last_30d":52,"last_7d":15,"last_24h":1},"max":287.5,"avg":93.52,"min":51.01,"latest":87},"image":"IMGURL","db_name":"Test-Artikel","dbID":"123456789"}],"__v":0,"createdAt":"2017-03-27T09:16:48.395Z"}"
Warning: Invalid argument supplied for foreach() in test.php on line 30

编辑：将 $dataArray 更改为$dataArray = json_decode($yourJsonArray,true);

错误 (4x)：警告：第 33 行 test.php 中的非法字符串偏移“图像”

第 33 行 = $image = $key['image'];

编辑：我丢弃了 $key Var 并得到了这个：

string(7) "tableID" string(4) "data" string(3) "__v" string(9) "createdAt"

我如何获得“数据”的元素？

Answer 1

像这样尝试：

$yourJsonArray = "You Json Array will come here";
//$dataArray = json_decode(json_encode($yourJsonArray),true);
$dataArray = json_decode($yourJsonArray,true); 
foreach($dataArray as $key => $value){
   //Here 0,1,2,3 Will be contained inside the $key variable.
   //Code to insert the data comes here
}