如何检查扫描器是否为特定字符串 + 任何正整数 [Java]

Question

我需要检查扫描仪是否持有这个：“添加（这里的任何整数）”这是代码：

import java.util.Scanner;
public class BottleGame {
    void startGame() {
        System.out.println("Welcome to the bottle game! Please type \"help\" to learn about the game.");
        System.out.println("If you already know how the game works, feel free to start!");
        Scanner scanner = new Scanner(System.in);
        commands(scanner);
    }
    void commands(Scanner myScanner) {
        boolean again = false;
        do {
            String response = myScanner.next();
            if (response.equals("help")) {
                System.out.println("+------------------------+");
                System.out.println("help - brings up this menu");
                System.out.println("add X - makes X bottles");
                System.out.println("remove X - deletes X bottles");
                System.out.println("flip - flips a bottle");
                System.out.println("+------------------------+");
                again = true;
            }
            //Need to check if response equals "add" + any integer here
        }
        while(again == true);
    }
}

我评论了我需要这个的地方，请在代码中寻找它。 任何帮助，将不胜感激。 提前致谢！

Answer 1

您可以为此使用正则表达式，例如"add\\\\s+\\\\d+" ，它将匹配单词 add 后跟一个或多个空格，然后是一个或多个带有String.matches(String)数字

} else if (response.matches("add\\s+\\d+")) {
    System.out.println("Add");
}

然后解析该值，您可以将数字分组并调用String.replaceAll(String, String)然后使用Integer.parseInt(String)像

} else if (response.matches("add\\s+\\d+")) {
    int v = Integer.parseInt(response.replaceAll("add\\s+(\\d+)", "$1"));
    System.out.println(v);
}