[英]how to sort this table with a model property
因此,我想在页面上添加功能,如果用户单击某列,则必须根据该列对表格进行排序(不确定我是否很清楚,因为我的英语水平也很差,所以这里有一个示例我要:点击“年龄”列=将所有用户(年龄从小到大)排序)
这是我的桌子
<table id="table1" >
<caption>Affectation d'Opacif</caption>
<!--Header du tableau (1ere ligne avec intitulés des champs : )-->
<thead>
<tr>
<th>Date</th>
<th>N° Client</th>
<th>Nom</th>
<th>Naf</th>
<th>Siret</th>
<th>Raison Sociale</th>
<th>Opacif</th>
</tr>
</thead>
<!--Body du tableau -->
<tbody>
@for (int i = 0; i < Model.beneficiaries.Count; i++)
{
<tr>
<td>@Model.beneficiaries[i].date</td>
<td class="taille100">@Model.beneficiaries[i].id</td>
<td>@Model.beneficiaries[i].lastname <br />
@Model.beneficiaries[i].firstname </td>
<td class="taille80">@Model.beneficiaries[i].naf</td>
<td>@Model.beneficiaries[i].siret</td>
<td class="taille300">@Model.beneficiaries[i].raisonsociale</td>
<td class="taille200">@Html.DropDownListFor(m => m.beneficiaries[i].opacif, new SelectList(Model.opacifs), "Selectionner un Opacif", new { @onchange = "CallChangefunc(this)", @naf= @Model.beneficiaries[i].naf, @siret= @Model.beneficiaries[i].siret })</td>
</tr>
}
</tbody>
</table>
这是我的控制器:
` public ActionResult Index()
{
var service = new OpacifService();
var beneficiaries = service.searchBeneficiaries();
var opacifs = service.searchOpacifs();
var viewModel = new OpacifViewModels { opacifs = opacifs, beneficiaries = beneficiaries };
return View(viewModel);
}
[HttpGet]
public JsonResult UpdateOpacif(string naf, string opacif, string siret)
{
JsonResult result = null;
var service = new OpacifService();
var valid = service.updateBeneficiary(naf, opacif, siret);
if (valid)
{
result = Json(new { code = 200, message = "Mise à jour effectuée !" }, JsonRequestBehavior.AllowGet);
}
else
{
result = Json(new { code = 417, message = "Une erreur est survenue lors de la mise à jour... Réessayez ou contactez l'administrateur" }, JsonRequestBehavior.AllowGet);
}
return result;
}
}`
我可能还会建议
foreach (var bc in Model.beneficiaries)
{
<tr>
<td>@bc.date</td>
<td class="taille100">@bc.id</td>
<td>@bc.lastname <br />
@bc.firstname </td>
<td class="taille80">@bc.naf</td>
<td>@Model.beneficiaries[i].siret</td>
<td class="taille300">@bc.raisonsociale</td>
<td class="taille200">@Html.DropDownListFor(m => m.beneficiaries[i].opacif, new SelectList(Model.opacifs), "Selectionner un Opacif", new { @onchange = "CallChangefunc(this)", @naf= @Model.beneficiaries[i].naf, @siret= @bc.siret })</td>
</tr>
}
您可以尝试如下操作:
1)更改表标题并添加链接以使用某些路由值打开相同的操作
...
// @Html.ActionLink(Linktext, Actionname, Controllername, Routevalues, Html Attributes)
<th> @Html.ActionLink("Age", "clients", "home", new { sortBy= "age" }, null) </th>
<th> @Html.ActionLink("Name", "clients", "home", new { sortBy= "name" }, null) </th>
...
请阅读本 ,以更好地了解@Html.ActionLink
方法的实际作用。 上面的示例将产生以下标记: <a href="/home/clients/age">Age</a>
2)现在您需要在Controller中的操作中添加逻辑
public ActionResult ActionName(string sortBy) {
// Do whatever is needed to collect the values. Let's call it valueCollection
Model.beneficiaries = valueCollection;
switch(sortBy) {
case "age":
Model.beneficiaries.orderBy(client => client.age);
break;
case "name":
Model.beneficiaries.orderBy(client => client.name);
break;
}
// You can add more sort options of course
}
由于您只提供了标记,所以我的答案有些猜测,但是您的Controller实际上应该像上面的那样。 我希望你能适应一些东西。 如果您有任何疑问,请告诉我。
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