[英]Searching through struct array for string entered by user
这只是我程序中的一个函数,应该搜索用户在struct数组中输入的字符串或整数。 我正在尝试做的是添加一条错误消息,并且当在结构数组中找不到所输入的字符串或整数时可以再次尝试的功能。 如果您输入正确的字符串或整数,它的搜索就很好,但是如果没有输入,则什么也不会发生。 我正在尝试更改它,但找不到解决方案。
我已经在switch语句中尝试了一种情况,但已经尝试了一段时间,但我需要对这三种情况都进行此操作。 但是到目前为止,我仅尝试了案例3。
search(struct items aItems[], int *num_items)
{
int choice_of_search, b=0, found_word=0, search_num, i=0, j=0, k=0;
char search_phrase[20]; struct items search[MAX];
printf("Choose what to search for? (1) Item number, (2) Name and (3) Balance. ");
scanf("%d", &choice_of_search);
while(choice_of_search < 1 || choice_of_search > 3)
{
printf("Wrong choice!\n");
printf("Choose what to search for? (1) Item number, (2) Name and (3) Balance. ");
scanf("%d", &choice_of_search);
}
switch(choice_of_search)
{
case 1:
printf("Item number?\n");
scanf("%d", &search_num);
for(i = 0; i < *num_items; i++)
{
if(search_num == aItems[i].itemnumber)
{
printf("Item number found!\n");
search[found_word]=aItems[i];
found_word+=1;
}
}
break;
case 2:
printf("Name?\n");
scanf("%s", search_phrase);
for(i = 0; i < *num_items; i++)
{
if(strstr(aItems[i].name, search_phrase))
{
printf("Name found!\n");
search[found_word]=aItems[i];
found_word+=1;
}
}
break;
case 3:
printf("Balance?\n");
scanf("%d", &search_num);
for(i = 0; i < *num_items; i++)
{
if(search_num == aItems[i].balance)
{
printf("Balance found!\n");
search[found_word]=aItems[i];
found_word+=1;
}
else
{
printf("Balance not found! Try again.\n");
printf("Balance?\n");
scanf("%d", &search_num);
}
}
break;
}
while(b < found_word)
{
printf("Item number: %d Name: %s Balance: %d\n", search[b].itemnumber, search[b].name, search[b].balance);
b++;
}
}
也许这可以帮助
int done;
...
...
case 3:
done = 0;
while(1);
{
printf("Balance?\n");
scanf("%d", &search_num);
for(i = 0; i < *num_items; i++)
{
if(search_num == aItems[i].balance)
{
printf("Balance found!\n");
search[found_word]=aItems[i];
found_word+=1;
done = 1;
}
}
if (done) break;
printf("Balance not found! Try again.\n");
}
break;
但是请注意,该代码不是用户友好的代码,因为它不允许用户在没有匹配项的情况下停止搜索。 因此,也许您应该考虑添加“您想重试”选项。
一个简单的方法可能是
printf("Balance not found! Would like to try again?.\n");
scanf(" %c", &some_char);
if (some_char != 'y') break;
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