复选框仅影响表中的一行

Question

我正在尝试，当我单击复选框时，如果我取消选中“当前” ID的隐藏字段，则该字段变为可见；而当我单击此复选框时，仅影响表的第一行，而其他行则不可见。不会影响何时选中或取消选中复选框。 以下是html代码

<table class="table table-bordered">
 <tr>
    <td><strong> Name</strong></td>
    <td><strong>Email</strong></td>
    <td><strong>Phone</strong></td>
    <td><strong>Cnic</strong></td>
    <td><strong>Attendence</strong></td>
    <td><strong>Status</strong></td>
  </tr> 
 <?php foreach($user as $USER){?>
  <form method="post" action="">
 <tr>
    <td>
      <input  type="text" name="name" value="<?=$USER->name;?>" readonly>
      <input type="hidden" name="u_id" value="<?=$USER->u_id;?>">
    </td>
    <td>
      <input type="text" name="email" value="<?=$USER->email;?>" readonly>
    </td>
    <td>
      <input type="text" name="phone" value="<?=$USER->phone;?>" readonly>
    </td>
    <td>
      <input type="text" name="cnic" value="<?=$USER->cnic;?>" readonly>
    </td>
    <td style="text-align: center">
      <input type="checkbox"name="checkbox"id="checkbox" onclick="visibility()">
    </td>
    <td>
      <span style="visibility: hidden; color: green;"><input type="text" name="att" value="Present" id="present"></span>
      <span style="visibility: hidden; color: red;"><input type="text" name="att" value="Absent" id="absent"></span>
    </td>
  </tr>     
    <?php }?>  
 </form>
</table>

以下是JavaScript代码

 <script type="text/javascript">
      function visibility() {
        if (document.getElementById("checkbox") . checked == true){
          document.getElementById("present").style.visibility ="visible";
          document.getElementById("absent").style.visibility = "hidden";
        }else{
          document.getElementById("absent").style.visibility = "visible";
          document.getElementById("present").style.visibility = "hidden";
        }     
      }
  </script>

Answer 1

我会这样做

 <span style="visibility: hidden; color: green;"><input type="text" name="att" value="Present" class="present"></span>
      <span style="visibility: hidden; color: red;"><input type="text" name="att" value="Absent" class="absent"></span>


<script type="text/javascript">
      function visibility() {
        if (document.getElementsByClassName("checkbox") . checked == true){
          document.getElementsByClassName("present").style.visibility ="visible";
          document.getElementsByClassName("absent").style.visibility = "hidden";
        }else{
          document.getElementsByClassName("absent").style.visibility = "visible";
          document.getElementsByClassName("present").style.visibility = "hidden";
        }     
      }
  </script>

Answer 2

请尝试以下方法：

• 呈现表单时，还将用户ID作为参数发送给visibility方法。

   onclick="visibility(<?=$USER->u_id;?>)" 

• 通过将用户ID附加到id属性来设置不存在和当前字段的ID。

   <span style="visibility: hidden; color: green;"><input type="text" name="att" value="Present" id="present<?=$USER->u_id;?>"></span> <span style="visibility: hidden; color: red;"><input type="text" name="att" value="Absent" id="absent<?=$USER->u_id;?>"></span> 

• 同样设置复选框的ID。

   <input type="checkbox"name="checkbox"id="checkbox<?=$USER->u_id;?>" onclick="visibility(<?=$USER->u_id;?>)"> 

• 使用作为参数发送给visibility方法的用户ID来标识元素的ID。

   function visibility(id) { if (document.getElementById("checkbox"+id) . checked == true){ document.getElementById("present"+id).style.visibility ="visible"; document.getElementById("absent"+id).style.visibility = "hidden"; }else{ document.getElementById("absent"+id).style.visibility = "visible"; document.getElementById("present"+id).style.visibility = "hidden"; } } 

 <script type="text/javascript"> function visibility(id) { if (document.getElementById("checkbox"+id) . checked == true){ document.getElementById("present"+id).style.visibility ="visible"; document.getElementById("absent"+id).style.visibility = "hidden"; }else{ document.getElementById("absent"+id).style.visibility = "visible"; document.getElementById("present"+id).style.visibility = "hidden"; } } </script> 

 <table class="table table-bordered"> <tr> <td><strong> Name</strong></td> <td><strong>Email</strong></td> <td><strong>Phone</strong></td> <td><strong>Cnic</strong></td> <td><strong>Attendence</strong></td> <td><strong>Status</strong></td> </tr> <?php foreach($user as $USER){?> <form method="post" action=""> <tr> <td> <input type="text" name="name" value="<?=$USER->name;?>" readonly> <input type="hidden" name="u_id" value="<?=$USER->u_id;?>"> </td> <td> <input type="text" name="email" value="<?=$USER->email;?>" readonly> </td> <td> <input type="text" name="phone" value="<?=$USER->phone;?>" readonly> </td> <td> <input type="text" name="cnic" value="<?=$USER->cnic;?>" readonly> </td> <td style="text-align: center"> <input type="checkbox"name="checkbox"id="checkbox<?=$USER->u_id;?>" onclick="visibility(<?=$USER->u_id;?>)"> </td> <td> <span style="visibility: hidden; color: green;"><input type="text" name="att" value="Present" id="present<?=$USER->u_id;?>"></span> <span style="visibility: hidden; color: red;"><input type="text" name="att" value="Absent" id="absent<?=$USER->u_id;?>"></span> </td> </tr> <?php }?> </form> </table> 

Answer 3

id必须是唯一的。

在您的函数中仅添加参数，例如onclick =“ visibility（1）”-对于第一行并传递2插入的1，依此类推，也请对您的id id =“ present_1”和id =“ absent_1”执行此操作，依此类推， js功能如下

  function visibility(no) {
    if (document.getElementById("checkbox") . checked == true){
      document.getElementById("present_"+no).style.visibility ="visible";
      document.getElementById("absent_"+no).style.visibility = "hidden";
    }else{
      document.getElementById("absent_"+no).style.visibility = "visible";
      document.getElementById("present_"+no).style.visibility = "hidden";
    }     
  }

希望它的工作