使用扫描仪读取文本文件，为单词创建一个字符串，为数字生成一个int数组

Question

输入我的文件名后，它可以编译但不执行任何操作。

这是用于解码程序的，其中文本文件中有一个字符串（关键字短语），并且有一个数字代码，您必须通过在字符串的索引中查找来解码它们。

示例文本文件：

六种完美质量的黑色珠宝令州长大为惊讶

35 10 10 33 9 24 3 17 41 8 3 20 51 16 38 44 47 32 33 10 19 38 35 28 49

使用数字作为关键短语的字符索引，将其解码为“在黎明时攻击桥梁” 。

空格和重复的字母也计算在内。

public static void main (String[] args)
{

sc = new Scanner( System.in );
System.out.print("File name? ");

try
{
  String fileName = sc.next().trim(); //requests file name then takes out spaces
  sc = new Scanner( new File(fileName) );  

  String key = ""; 

  while (sc.hasNext()) // looks for data  
  {
    if (sc.hasNextLine()) //if data is a string
      key = sc.nextLine(); //it is stored as key
  }

  int codeLen = 0;

  while ( sc.hasNext() )   
  {
    if ( sc.hasNextInt() )  // if the data is an integer
      codeLen++; //calculates # of integers
  }

  int[] code = new int[codeLen]; //creates array of the size of the number of intergers in file
  int num;

  while ( sc.hasNext() )   
  {
    if ( sc.hasNextInt() )  
    {
      num = sc.nextInt(); //each number found is stored

      for(int x = 0; x < codeLen; x++){ 
        code[x] = num; //adds num to the array
      }
    }
  }

  System.out.println(secretcodeM(key, code)); // prints out secret message

}

}

catch ( FileNotFoundException ex )
{ 
  System.out.println("File not found." );
  System.out.println("Run the program again." );
} 

不太重要，但以防万一。

public static String secretcodeM(String key, int[] code){

int codeLen = code.length;

StringBuilder secret = new StringBuilder(codeLen); 

for (int x= 0; x < codeLen; x++) //goes through code
{
  int index = code[x]; //finds the numbers in code and stores as index

  char a = key.charAt(index); //finds the character in the index in key

  secret.append(a); // add a to secret 
}

return secret.toString();
}

如果您能说出问题所在，可以请您帮忙吗？

Answer 1

这是我的代码：

    String fileName = "PathToFile";
    List<String> strings = new ArrayList<String>();

    //read file to an ArrayList
    try (BufferedReader br = new BufferedReader(new FileReader(fileName))) {

        String line;
        while ((line = br.readLine()) != null) {
            strings.add(line);
        }

    } catch (IOException e) {
        e.printStackTrace();
    }

    String code = strings.get(0);
    String key = strings.get(1);

    //cast String key to int[]
    String[] numbers = key.split(" ");
    int[] keyArr = new int[numbers.length];
    for(int i = 0; i < numbers.length; i++) {
        keyArr[i] = Integer.parseInt(numbers[i]);
    }

然后您可以调用secretcodeM(code, keyArr)