Yii2列中where子句不明确

Question

导致错误的查询如下：

 $query = $model::find()
        ->leftJoin('reseller_config', 'reseller_rate.resellerref = reseller_config.resellerref')
        ->select('reseller_rate.*, reseller_config.resellerref AS rate_increase');

生成的sql如下：

SELECT COUNT(*) FROM `reseller_rate` LEFT JOIN `reseller_config` ON reseller_rate.resellerref = rc.resellerref WHERE `resellerref`=56

我知道这是行不通的，因为这些字段被命名为相同的字段，并且它不知道要抓住哪个字段。

有人知道我该如何解决吗？

Answer 1

$query = $model::find()
    ->leftJoin('reseller_config', 'reseller_rate.resellerref = reseller_config.resellerref')
    ->select('reseller_rate.*', 'reseller_config.resellerref AS rate_increase');

您可以将其与查询bulider一起使用：

 $model = (new Query())
            ->select(['reseller_rate.*', 'reseller_config.resellerref AS rate_increase')
            ->from('reseller_rate')
            ->leftJoin('reseller_config', 'reseller_rate.resellerref = reseller_config.resellerref')
            ->all();