![](/img/trans.png)
[英]Typescript: Function find for array is working but if I check if it's returning a value with an if statement, it doesn't work
[英]Exported function doesn't work in if statement in TypeScript
我有一个函数(getLocalSecurity),它从命令提示符处获取一个参数并返回布尔值,如下所示:
server.ts:
import { getDataService } from './service';
import { getInternalService } from './internal/service';
import { ServiceFactory } from './services/serviceFactory';
import { loggers } from 'winston';
const LOG = loggers.get('server');
const mainApp = getDataService();
const cla = require('command-line-arguments');
const params = cla.getCommandLineArguments();
export function getLocalSecurity(): boolean {
return params.LOCAL_SECURITY;
}
LOG.info('Starting server on port 9090...');
在另一个typeScript文件上,我想使用它:
import {getLocalSecurity} from './server';
if (getLocalSecurity()) {
console.log('access denied', getLocalSecurity());
return Promise.resolve({});
}
当我在命令提示符下使用以下语句时, console.log中的 getLocalSecurity为false,但如果条件为true,则为LocalLocalSecurity。 问题是什么? 我该如何解决?
npm run start --- LOCAL_SECURITY -false
return不是布尔值,它是字符串,我不知道为什么! 在if条件下,我们必须使用以下内容:
if (getLocalSecurity() === 'false')....
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.