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如何创建查询以合并两行或三行以获得重复的ID

[英]How to create a query to combine two or three rows for duplicated IDs

我正在尝试创建一个select语句,以合并任何特定列上重复ID的值。

我的桌子是:

ID   Name
---------
01   A
01   B
02   C
03   D

如何选择获取值,例如:ID的01 A,B:01。当前,当我使用Tablename中的Select *时,它将两行列出01 ID。 我只想将其合并为一行,对于任何重复的行,Name应该与逗号结合。

新代码:

select Name, ID = REPLACE
  ((select Surname AS [data()]
        FROM Mytable
        WHERE Name = d. Name
        ORDER BY Name FOR XML path('')), ' ', REQUIRED SEPERATOR)
FROM Mytable d
WHERE Name IS NOT NULL
GROUP BY Name

非常感谢你!

SQL小提琴

MS SQL Server 2014架构设置

create table t (id int not null, name nvarchar(max) not null)
insert t (id, name) values 
  (1, 'A'), 
  (1, 'B'),
  (1, 'C'), 
  (2, 'A'),
  (2, 'D'), 
  (3, 'A'),
  (3, 'F'), 
  (3, 'E')

查询1

    select id, REPLACE
      ((select name AS [data()]
            FROM t as t1
            WHERE t1.id = t0.id
            ORDER BY Name FOR XML path('')), ' ', ',')
    FROM t as t0
    GROUP BY id

结果

| id |       |
|----|-------|
|  1 | A,B,C |
|  2 |   A,D |
|  3 | A,E,F |

更新要处理名称中已经存在的空格,我们可以在分组之前将其替换为下划线,并在之后进行替换:

  select id, replace(REPLACE
  ((select replace(name, ' ', '_') AS [data()]
        FROM t as t1
        WHERE t1.id = t0.id
        ORDER BY Name FOR XML path('')), ' ', ','), '_', ' ')
FROM t as t0
GROUP BY id

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