[英]How to create a query to combine two or three rows for duplicated IDs
我正在尝试创建一个select语句,以合并任何特定列上重复ID的值。
我的桌子是:
ID Name
---------
01 A
01 B
02 C
03 D
如何选择获取值,例如:ID的01 A,B:01。当前,当我使用Tablename中的Select *时,它将两行列出01 ID。 我只想将其合并为一行,对于任何重复的行,Name应该与逗号结合。
新代码:
select Name, ID = REPLACE
((select Surname AS [data()]
FROM Mytable
WHERE Name = d. Name
ORDER BY Name FOR XML path('')), ' ', REQUIRED SEPERATOR)
FROM Mytable d
WHERE Name IS NOT NULL
GROUP BY Name
非常感谢你!
MS SQL Server 2014架构设置 :
create table t (id int not null, name nvarchar(max) not null)
insert t (id, name) values
(1, 'A'),
(1, 'B'),
(1, 'C'),
(2, 'A'),
(2, 'D'),
(3, 'A'),
(3, 'F'),
(3, 'E')
查询1 :
select id, REPLACE
((select name AS [data()]
FROM t as t1
WHERE t1.id = t0.id
ORDER BY Name FOR XML path('')), ' ', ',')
FROM t as t0
GROUP BY id
结果 :
| id | |
|----|-------|
| 1 | A,B,C |
| 2 | A,D |
| 3 | A,E,F |
更新要处理名称中已经存在的空格,我们可以在分组之前将其替换为下划线,并在之后进行替换:
select id, replace(REPLACE
((select replace(name, ' ', '_') AS [data()]
FROM t as t1
WHERE t1.id = t0.id
ORDER BY Name FOR XML path('')), ' ', ','), '_', ' ')
FROM t as t0
GROUP BY id
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