[英]How to get a specific value from json data in swift
我试图从json中提取某个值。 在这种情况下,我尝试从以下示例中获取“ isethanawake”的值,该值应为1:
可选([[{“ isethanawake”:1,“ name”:“ Ethan”},{“ ismadisonawake”:0,“ name”:“ Madison”},{“ ismomawake”:0,“ name”:“ Mom”} ,{“ isdadawake”:0:“ name”:“ Dad”}]
这是我的代码,它没有将变量设置为1
var isethanawake = 0
var ismadisonawake = 0
var ismomawake = 0
var isdadawake = 0
request2.httpBody = postString2.data(using: String.Encoding.utf8)
let task2 = URLSession.shared.dataTask(with: request2 as URLRequest){
data, response, error in
if error != nil{
print("error = \(error)")
return
}
print("response = \(response)")
let responseString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("responseString = \(responseString)")
do{
let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
if let parseJSON1 = json {
isethanawake = parseJSON1["isethanawake"] as! Int
}
if let parseJSON2 = json{
ismadisonawake = parseJSON2["ismadisonawake"] as! Int
}
if let parseJSON3 = json{
ismomawake = parseJSON3["ismomawake"] as! Int
}
if let parseJSON4 = json{
isdadawake = parseJSON4["isdadawake"] as! Int
}
print("hello" + String(isethanawake))
}catch{
print(error)
}
它是从以下php脚本获取数据的:
$jsonarray = array();
if(mysqli_num_rows($ethanresult)){
$returnValue1 = array("isethanawake"=> 1, "name"=> "Ethan");
array_push($jsonarray, $returnValue1);
}else{
$returnValue1 = array("isethanawake"=> 0, "name"=> "Ethan");
array_push($jsonarray, $returnValue1);
}
if(mysqli_num_rows($madisonresult)){
$returnValue2 = array("ismadisonawake"=> 1, "name"=> "Madison");
array_push($jsonarray, $returnValue2);
}else{
$returnValue2 = array("ismadisonawake"=> 0, "name"=> "Madison");
array_push($jsonarray, $returnValue2);
}
if(mysqli_num_rows($momresult)){
$returnValue3 = array("ismomawake"=> 1, "name"=> "Mom");
array_push($jsonarray, $returnValue3);
}else{
$returnValue3 = array("ismomawake"=> 0, "name"=> "Mom");
array_push($jsonarray, $returnValue3);
}
if(mysqli_num_rows($dadresult)){
$returnValue4 = array("isdadawake"=> 1, "name"=> "Dad");
array_push($jsonarray, $returnValue4);
}else{
$returnValue4 = array("isdadawake"=> 0, "name"=> "Dad");
array_push($jsonarray, $returnValue4);
}
echo json_encode($jsonarray);
}
谢谢
如您所说,您的JSON结构为:
可选([[{“ isethanawake”:1,“ name”:“ Ethan”},{“ ismadisonawake”:0,“ name”:“ Madison”},{“ ismomawake”:0,“ name”:“ Mom”} ,{“ isdadawake”:0:“ name”:“ Dad”}]
在Swift中,json的类型将为[[String:Any]]?。 这意味着您有一个词典数组。 该错误表明您无法使用String下标数组。 这意味着您需要遍历子数组来执行您想要的代码:
do{
let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
if let json as? [[String: Any]]{
for arrayJSONObj in json {
isethanawake = arrayJSONObj["isethanawake"] as? Int ?? 0
ismadisonawake = arrayJSONObj["ismadisonawake"] as? Int ?? 0
ismomawake = arrayJSONObj["ismomawake"] as? Int ?? 0
isdadawake = arrayJSONObj["isdadawake"] as? Int ?? 0
}
}
print("hello" + String(isethanawake))
}catch{
print(error)
}
我也建议您为您的值(这两个??)使用默认值,而不是强行解开默认值以防止您的应用崩溃。
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