[英]Swift iOS -How to continue running a DispatchSemaphore combined with DispatchGroup()
[英]Swift 4 async call with for loop execute in order using DispatchGroup, DispatchQueue and DispatchSemaphore
我想在 swift 中按顺序运行 for 循环,DispatchGroup 会将它们一起触发,所以我想使用 DispatchQueue 和 DispatchSemaphore 来实现我的目标。 我的程序运行失败,如何强制他们等待并一一运行?
let dispatchGroup = DispatchGroup()
let dispatchQueue = DispatchQueue(label: "taskQueue")
let dispatchSemaphore = DispatchSemaphore(value: 1)
for c in self.categories {
dispatchSemaphore.wait()
dispatchQueue.async(group: dispatchGroup) {
if let id = c.categoryId {
dispatchGroup.enter()
self.downloadProductsByCategory(categoryId: id) { success, data in
if success, let products = data {
self.products.append(products)
}
dispatchSemaphore.signal()
dispatchGroup.leave()
}
}
}
}
dispatchGroup.notify(queue: dispatchQueue) {
self.refreshOrderTable { _ in
self.productCollectionView.reloadData()
NVActivityIndicatorPresenter.sharedInstance.stopAnimating()
}
}
感谢Palle ,这是我的最终代码:
let dispatchGroup = DispatchGroup()
let dispatchQueue = DispatchQueue(label: "taskQueue")
let dispatchSemaphore = DispatchSemaphore(value: 0)
dispatchQueue.async {
for c in self.categories {
if let id = c.categoryId {
dispatchGroup.enter()
self.downloadProductsByCategory(categoryId: id) { success, data in
if success, let products = data {
self.products.append(products)
}
dispatchSemaphore.signal()
dispatchGroup.leave()
}
dispatchSemaphore.wait()
}
}
}
dispatchGroup.notify(queue: dispatchQueue) {
DispatchQueue.main.async {
self.refreshOrderTable { _ in
self.productCollectionView.reloadData()
}
}
}
您可以将整个循环放在一个块中,而不是只将下载函数放在一个块中:
dispatchQueue.async {
for c in self.categories {
if let id = c.categoryId {
self.downloadProductsByCategory(categoryId: id) { success, data in
if success, let products = data {
self.products.append(products)
}
dispatchSemaphore.signal()
}
dispatchSemaphore.wait()
}
}
}
您可以通过使用 compactMap 来解开您的产品 ID 来简化您的代码:
for id in self.categories.compactMap({$0.categoryId}) { ... }
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