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[英]How to join to a JOINED subclass in a Hibernate / JPA 2.0 CriteriaQuery?
[英]Hibernate/JPA querying embeddable property of a joined subclass
我有以下实体:ShoppingCart,抽象类User和扩展User的EndUser。 AddressDetails是一个嵌入到EndUser实体中的可嵌入对象。
我的查询如下所示: SELECT sc FROM ShoppingCart sc JOIN sc.endUser as endUser WHERE endUser.name EQ someName and endUser.addressDetails.zip EQ 1234
当我删除WHERE子句的第二部分,而只保留endUser.name部分时,一切正常(name是endUser实体类的属性,后者是User实体类的子类)。 但是,当我尝试整个查询时,我得到:
org.hibernate.QueryException: could not resolve property: zip of:
购物车:
@Entity
public class ShoppingCart {
...
@ManyToOne(fetch = FetchType.LAZY)
@JoinTable
private EndUser endUser;
}
用户:
@Entity
public abstract class User {
...
}
最终用户:
@Entity
public class EndUser extends User {
...
@Column
private String name;
@Embeded
private AddressDetails addressDetails;
...
}
详细地址:
@Embeddable
public class AddressDetails {
...
private int zip;
...
}
我实际上发现了问题。
当我在ShoppingCart和endUser之间的@ManyToOne退役上将FetchType更改为EAGER时,查询有效。
因此应该是:
@ManyToOne(fetch = FetchType.EAGER)
@JoinTable
private EndUser endUser;
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