从字符串中删除数组中所有出现的字符

Question

我正在构建一个应用程序，需要从其输入中裁剪大量文本，我想将“正在删除”列表移动到一个数组中，以使其易于管理。

const badWords = ['jamie', 'hutber'];
const naughtyString = 'Jamie Hutber everybody likes Jamie Chocolate';

预期输出为：

'everybody likes Chocolate'

因此，如果不清楚，我想从字符串naughtySting中删除在badWords中出现的所有事件...

Answer 1

您在正确的路径上，将句子拆分为一个数组，删除所有出现的内容：

let goodSentence = naughtyString.split(' ').filter(s => badWords.indexOf(s.toLowerCase()) === -1).join(' ');

Answer 2

如果它是专门针对badWords的，则可以有以下内容：

var result = naughtyString;
badWords.forEach(function(badWord){
     result = result.split(new RegExp(badWord,'i')).join(Array(badWord.length).join("*"));
});

结果==“ **** *****每个人都喜欢****巧克力”

Answer 3

对badWords单次迭代：

 const badWords = ['jamie', 'hutber']; let naughtyString = 'Jamie Hutber everybody likes Jamie Chocolate'; badWords.forEach(bad => { let rgx = new RegExp(bad, 'ig'); naughtyString = naughtyString.replace(rgx, ''); }); console.log(naughtyString); 

Answer 4

我想出了另一个更容易理解的想法：

 const badWords = ['jamie', 'hutber']; let naughtyString = 'Jamie Hutber everybody likes Jamie Chocolate'; const rgx = new RegExp(badWords.join('|'), 'gi'); let cleanString = naughtyString.replace(rgx, ''); console.log(cleanString); 

Answer 5

您还需要检查大小写。.由于您的badwords均为小写字母，但是您的搜索字符串混合使用大小写。

 const badWords = ['jamie', 'hutber']; const naughtyString = 'Jamie Hutber everybody likes Jamie Chocolate'; // 'everybody likes Chocolate' function notBadWord(f) { return !badWords.includes(f.toLowerCase()); } var out = naughtyString.split(/\\s/).filter(notBadWord).join(" "); console.log(out);