繁体   English   中英

使用一个查询从两个 SQL 表中分页。 最快的方式

[英]Pagination from two SQL Tables with one query. Fastest Way

我有一个简单的数据库:

Table 1: Object                    Table 2: Data
id | type | added                  object_id | key     | value
------------------------           -----------------------------
1  | app  | 2017                   1         | name     | ...
2  | app  | 2017                   2         | name     | ...
3  | win  | 2017                   2         | version  | ...
                                   2         | dev_name | ...
                                   2         | lang     | ...

我创建了一个简单的分页,仅显示来自类型应用程序的 5 个对象及其数据表中的信息:

example code:
$sth = $dbh->prepare("SELECT * FROM object WHERE type = 'app' LIMIT 5");
$sth->execute;
$object = $sth->fetchAll(PDO::FETCH_ASSOC);

foreach($object as $rows) {
    $sth = $dbh->prepare("SELECT * FROM data WHERE id = $rows['id']");
    $sth->execute;
    $data = $sth->fetchAll(PDO::FETCH_ASSOC);

    echo $data['name'];
    echo $data['version'];
    echo $object['added'];
    ...

有没有更好的办法? 因为这是一个非常糟糕的解决方案,我只想查询一次我得到这样的获取数组:

array(
       // app with id = 1 in object table
       [1] => array(
                     // data from the app with id = 1 in data table
                     [name] => ...
                     [version] => ...
                     [dev_name] => ...
                     [lang] => ...
       // app with id = 2 in object table
       [2] => array(
                     // data from the app with id = 2 in data table
                     [name] => ...
                     [version] => ...
                     [dev_name] => ...
                     [lang] => ...
...

一个查询:

SELECT * FROM object inner join data on data.id_object=object.id WHERE object.type = 'app' LIMIT 5

此查询从两个表中返回信息和关联数据。 我想这就是你想要的

如果要按第一个表的 id 分组,也可以执行此查询

SELECT * FROM object inner join data on data.id_object=object.id WHERE object.type = 'app' group by object.id LIMIT 5

或者

SELECT Distinct(object.id), object.type, .... FROM object inner join data on data.id_object=object.id WHERE object.type = 'app'  LIMIT 5

考虑字符串比较使用 LIKE 而不是 =

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM