[英]Fetching data from MongoDb with Spring
我正在根据酒店搜索测试一种情况。 所以我做了3个模型班,分别是酒店,房间和空房
下面是我们正在使用的三个Model类。
酒店.java
@Document(collection =“ Hotels”)公共类酒店{
@Id
private String id;
private String name;
private Long pincode;
@Field("roomCategoryDocs")
private Object roomCategoryDocs;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Long getPincode() {
return pincode;
}
public void setPincode(Long pincode) {
this.pincode = pincode;
}
public Object getRoomCategoryDocs() {
return roomCategoryDocs;
}
public void setRoomCategoryDocs(Object roomCategoryDocs) {
this.roomCategoryDocs = roomCategoryDocs;
}
@Override
public String toString() {
return String.format("Hotel [id=%s, name=%s, pincode=%s, roomCategoryDocs=%s]", id, name, pincode,
roomCategoryDocs);
}
}
Room.java
@Document(collection =“ rooms”)公共课堂Room {
@Id
private String id;
private String frontImg;
private String category;
private ObjectId hotelId;
@Field("availabilityDocs")
private Object availabilityDocs;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getFrontImg() {
return frontImg;
}
public void setFrontImg(String frontImg) {
this.frontImg = frontImg;
}
public String getCategory() {
return category;
}
public void setCategory(String category) {
this.category = category;
}
public ObjectId getHotelId() {
return hotelId;
}
public void setHotelId(ObjectId hotelId) {
this.hotelId = hotelId;
}
public Object getAvailabilityDocs() {
return availabilityDocs;
}
public void setAvailabilityDocs(Object availabilityDocs) {
this.availabilityDocs = availabilityDocs;
}
@Override
public String toString() {
return String.format("Room [id=%s, frontImg=%s, category=%s, hotelId=%s, availabilityDocs=%s]", id, frontImg,
category, hotelId, availabilityDocs);
}
}
Availability.java
@Document(collection =“ rooms”)公共类可用性{
@Id
private String id;
private ObjectId roomId;
private Integer availability;
private Double rate;
private String date;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public ObjectId getRoomId() {
return roomId;
}
public void setRoomId(ObjectId roomId) {
this.roomId = roomId;
}
public Integer getAvailability() {
return availability;
}
public void setAvailability(Integer availability) {
this.availability = availability;
}
public Double getRate() {
return rate;
}
public void setRate(Double rate) {
this.rate = rate;
}
public String getDate() {
return date;
}
public void setDate(String date) {
this.date = date;
}
@Override
public String toString() {
return String.format("Availability [id=%s, roomId=%s, availability=%s, rate=%s, date=%s]", id, roomId,
availability, rate, date);
}
}
这些存储在两个mongodb集合中,一个用于酒店,另一个用于房间和可用性。
下面是我们从中获取数据的Controller类的方法
@GetMapping(value =“ / hotel”)公共列表getAllHotel(){
Aggregation agg = newAggregation(match(Criteria.where("pincode").lt(800080)),
lookup("rooms", "_id", "hotelId", "roomCategoryDocs"), unwind("roomCategoryDocs", true),
lookup("rooms", "roomCategoryDocs._id", "roomId", "roomCategoryDocs.availabilityDocs"),
unwind("roomCategoryDocs", true),
group("_id").first("name").as("name").last("pincode").as("pincode").push("roomCategoryDocs").as("roomCategoryDocs")
);
// Convert the aggregation result into a List
AggregationResults<Hotel> groupResults = mongoTemplate.aggregate(agg, "Hotels", Hotel.class);
List<Hotel> result = groupResults.getMappedResults();
return result;
}
现在,在获取酒店数据时,我们将获取房间和空房情况下的所有数据。
我们得到的输出:
[
{
"id": "59fabce1acd8be143417b101",
"name": "Elegance",
"pincode": 700042,
"availabilityDocs": [
{
"id": "59fabe39acd8be143417b103",
"frontImg": "google.com/1234",
"category": "Deluxe",
"hotelId": {
"timestamp": 1509604577,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552641,
"timeSecond": 1509604577,
"time": 1509604577000,
"date": 1509604577000
},
"availabilityDocs1": [
{
"id": "59fabf66acd8be14344a2df3",
"roomId": {
"timestamp": 1509604921,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552643,
"timeSecond": 1509604921,
"time": 1509604921000,
"date": 1509604921000
},
"availability": 10,
"rate": 4000,
"date": "2017-10-11"
},
{
"id": "59fae259acd8be264cf4430f",
"roomId": {
"timestamp": 1509604921,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552643,
"timeSecond": 1509604921,
"time": 1509604921000,
"date": 1509604921000
},
"availability": 11,
"rate": 4001,
"date": "2017-10-12"
}
]
}
]
}
]
但是,现在我们陷入了一个问题,即基于date属性进行搜索。
预期输出:
在这里,我们只想获取2017年10月10日以来的数据。
{
"id": "59fabce1acd8be143417b101",
"name": "Elegance",
"pincode": 700042,
"availabilityDocs": [
{
"id": "59fabe39acd8be143417b103",
"frontImg": "google.com/1234",
"category": "Deluxe",
"hotelId": {
"timestamp": 1509604577,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552641,
"timeSecond": 1509604577,
"time": 1509604577000,
"date": 1509604577000
},
"availabilityDocs1": [
{
"id": "59fabf66acd8be14344a2df3",
"roomId": {
"timestamp": 1509604921,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552643,
"timeSecond": 1509604921,
"time": 1509604921000,
"date": 1509604921000
},
"availability": 10,
"rate": 4000,
"date": "2017-10-11"
}
}
以下是json集合示例酒店集合:
{ "_id" : ObjectId("59fabce1acd8be143417b101"), "name" : "Elegance", "pincode" : NumberLong(700042), "_class" : "com.lara.mongodb.domain.Hotel" }
客房集合示例:
{ "_id" : ObjectId("59fabf66acd8be14344a2df3"), "roomId" : ObjectId("59fabe39acd8be143417b103"), "availability" : 10, "rate" : 4000, "date" : "2017-10-11", "_class" : "com.lara.mongodb.domain.Availability" }
我愿意接受关于设计和任何其他想法的建议,因为我是新来的。 任何帮助将不胜感激。 谢谢。
老实说,我对您如何在同一个集合中编写两个实体有些困惑。 从您添加的示例集合中,我可以说出一个缺失。 但是抛开这个。 我将您的最终结果用作切入点。 所以我从以下开始:
{
"id": "59fabce1acd8be143417b101",
"name": "Elegance",
"pincode": 700042,
"availabilityDocs": [
{
"id": "59fabe39acd8be143417b103",
"frontImg": "google.com/1234",
"category": "Deluxe",
"hotelId": {
"timestamp": 1509604577,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552641,
"timeSecond": 1509604577,
"time": 1509604577000,
"date": 1509604577000
},
"availabilityDocs1": [
{
"id": "59fabf66acd8be14344a2df3",
"roomId": {
"timestamp": 1509604921,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552643,
"timeSecond": 1509604921,
"time": 1509604921000,
"date": 1509604921000
},
"availability": 10,
"rate": 4000,
"date": "2017-10-11"
},
{
"id": "59fae259acd8be264cf4430f",
"roomId": {
"timestamp": 1509604921,
"machineIdentifier": 11327678,
"processIdentifier": 5172,
"counter": 1552643,
"timeSecond": 1509604921,
"time": 1509604921000,
"date": 1509604921000
},
"availability": 11,
"rate": 4001,
"date": "2017-10-12"
}
]
}
]
}
所以这是您进行汇总后的结果。 现在您只需要2017-10-11
可用的2017-10-11
。 但是在结果数组中,您同时获得“ 2017-10-12”和“ 2017-10-11”。
因此,如果我得到了上述结果,则必须添加以下内容:
{
$unwind: "$availabilityDocs"
},
{
$unwind: "$availabilityDocs.availabilityDocs1"
},
{
$match: {
"availabilityDocs.availabilityDocs1.date" : "2017-10-11"
}
}
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