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[英]How do you re-route multiple Express.js paths and return a single result?
[英]Express js:multiple route files into single file
在我的express.js应用程序中,我按照以下方式组织路线
路由/comment.js(处理所有评论路由)
var express = require('express');
var router = express.Router();
var comment = require('../controller/comment');
router.route('/new').get(comment.create);
module.exports = router;
route / post.js(处理所有发布路线)
var express = require('express');
var router = express.Router();
var post = require('../controller/post');
router.route('/new').get(post.create);
module.exports = router;
我以这种方式将其包含在app.js文件中
//need to include these declarations into another file and include that file here
//eg: require('config/main-routes');
/*
routes like comment/new
*/
var comment = require('./routes/comment');
app.use('/comment',comment);
/*
routes like post/new
*/
var post = require('./routes/post');
app.use('/post',post)
效果很好,但是我想将其包含到另一个文件中,比如说config/route-main.js
并将其链接到app.js
文件
我怎样才能做到这一点??
在app.js
包括
var routes = require('./config/route-main');
app.use('/',routes);
并在route-config.js中
var express = require('express');
var router = express.Router();
var comment = require('./routes/comment');
var post = require('./routes/post');
router.use('/comment',comment);
router.use('/post',post)
module.exports = router
检查此链接http://katieleonard.ca/blog/2016/nested-routes-with-expressjs/
您的app.js
文件:
const Express = require('express');
const app = Express();
const Routes = require('./routes');
app.use('', Routes);
您的routes.js
文件:
const Express = require('express');
const Router = Express.Router();
const UsersController = require('./controllers/usersController');
Router.post('/users', UsersController.CreateUser);
module.exports = Router;
您的usersController.js
文件:
const CreateUser = (req, res, next) => {
// DO STUFF HERE
}
module.exports = {
CreateUser
}
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