[英]Row_Number with Teradata GROUPBY
我试图确定如何使用下面的结果集将ROW_NUMBER()
函数与TERADATA一起使用。 这是我尝试过的:
select col1, col2, ROW_NUMBER() OVER (ORDER by col2 )
FROM
(select col1, col2
from TABLE
ORDER BY col2) A
结果集
38 11/14/2016 1
38 11/15/2016 2
38 11/16/2016 3
38 11/17/2016 4
38 11/18/2016 5
38 11/19/2016 6
39 11/20/2016 7
39 11/21/2016 8
39 11/22/2016 9
39 11/23/2016 10
39 11/24/2016 11
39 11/25/2016 12
预期:
Col1 Col2 Col3
38 11/14/2016 1
38 11/15/2016 1
38 11/16/2016 1
38 11/17/2016 1
38 11/18/2016 1
38 11/19/2016 1
39 11/20/2016 2
39 11/21/2016 2
39 11/22/2016 2
39 11/23/2016 2
39 11/24/2016 2
39 11/25/2016 2
您需要添加PARTITION BY
:
SELECT col1,
col2,
ROW_NUMBER() OVER (PARTITION BY col1 ORDER by col2) AS row_index
FROM TABLE
ORDER BY col2
好吧,看来您确实需要:
SELECT col1,
col2,
DENSE_RANK() OVER (ORDER by col1) AS row_index
FROM TABLE
ORDER BY col2
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