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似乎在具有相同锁的一个线程正在休眠时,另一个线程能够获得该锁?

[英]How does it seem to appear that another thread is able to acquire the lock while one thread having the same lock is sleeping?

下面的代码-没有wait()和notify()方法:

package com.jay;

import java.util.Random;

public class Main {

    public static void main(String[] args) {
        Message message = new Message();
        (new Thread(new Writer(message))).start();
        (new Thread(new Reader(message))).start();
    }

}

class Message {
    private String message;
    private boolean empty = true;

    public synchronized String read() {
        while (empty) {

        }
        empty = true;
        return message;
    }

    public synchronized void write(String message) {
        while (!empty) {

        }
        empty = false;
        this.message = message;
    }
}

class Writer implements Runnable {
    private Message message;

    public Writer(Message message) {
        this.message = message;
    }

    public void run() {
        String[] messages = {
            "Humpty Dumpty sat on a wall",
            "Humpty Dumpty had a great fall",
            "All the king's horses and all the king's men",
            "Couldn't put Humpty together again"
        };

        Random random = new Random();

        for(int i=0; i<messages.length; i++) {
            message.write(messages[i]);
            try {
                Thread.sleep(random.nextInt(2000));
            } catch (InterruptedException e) {
                // TODO: handle exception
            }
        }
        message.write("Finished");
    }
}

class Reader implements Runnable {
    private Message message;

    public Reader(Message message) {
        this.message = message;
    }

    public void run() {
        Random random = new Random();

        for(String latestMessage = message.read(); !latestMessage.equals("Finished"); 
                latestMessage = message.read()) {
            System.out.println(latestMessage);

            try {
                Thread.sleep(random.nextInt(2000));
            } catch (InterruptedException e) {
                // TODO: handle exception
            }
        }
    }
}

大多数情况下,它会在控制台上打印并挂起:

Humpty Dumpty sat on a wall

Humpty Dumpty had a great fall

有时会打印所有四个消息。

我的问题是:当Writer线程已获得锁并仍在循环时,Reader线程如何执行read()方法中的代码?

我很困惑。 请帮我理解!

@Oliver Charlesworth的评论消除了我的疑虑。 我没有注意到读者每次离开同步方法时,读者都可以输入同步方法。 该程序挂起,因为将有一个阶段,其中一个线程处于休眠状态,并且“空”字段的值不会被修改,从而导致其中一个循环无限运行。 一旦实现了wait()和notify()方法,问题将得到解决!

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