Ajax的400错误请求
[英]400 bad request with Ajax
问题描述
嗨，我在这里尝试了所有可能的方法，并通读了数百个搜索结果，
当我将代码上传到服务器时，在xampp上本地时出现400错误，它工作正常。
我的目标是使用ajax运行php文件，我不需要发布数据，但是使用post是我设法使其运行savetodb.php的唯一方法。这是我的代码：专门查看ajax的成功回调
<html> <head> <link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous"> <script src="https://code.jquery.com/jquery-3.2.1.js" integrity="sha256-DZAnKJ/6XZ9si04Hgrsxu/8s717jcIzLy3oi35EouyE=" crossorigin="anonymous"></script> <link rel="stylesheet" type="text/css" href="style.css"> <script> $( document ).ready(function() { var high = document.getElementById('high'); var low = document.getElementById('low'); var closing = document.getElementById('closing'); var difference = document.getElementById('difference'); getData(); }); function getData() { $.ajax({ type: 'GET', url: 'https://api-fxpractice.oanda.com/v3/instruments/EUR_USD/candles?count=100', headers: { 'Content-Type': 'application/json', 'Authorization': 'Bearer token goes here' }, success: function(data){ $.ajax({ type: 'POST', data: data.candles[0], contentType: "application/json; charset=utf-8", dataType: "json", headers: {'Content-Type': 'application/json'}, url: 'savetodb.php', success: function(){ console.log(data); } }) } }).done(function(data) { var highNew = data.candles[0]['mid']['h']; var lowNew = data.candles[0]['mid']['l']; var closeNew = data.candles[0]['mid']['c']; var myArray = data.candles; var total = 0; var difftotal = 0; var diff = 0; for (var i = 0, l = data.candles.length; i < l; i++) { total += parseFloat(data.candles[i]['mid']['c']); diff = data.candles[i]['mid']['h'] - data.candles[i]['mid']['l']; difftotal += parseFloat(diff); } var diffAvg = difftotal / data.candles.length; var avg = total / data.candles.length; var dec = avg.toFixed(5) var dif = diffAvg.toFixed(10) high.innerHTML = highNew; low.innerHTML = lowNew; closing.innerHTML = dec; difference.innerHTML= dif; }); } setInterval(getData,5000); </script> </head> <body> <div class="container"> <div class="row"> <div class="col-lg-12"><h1 class="title">EUR/USD</h1></div> <div class="high alert alert-success col-lg-6"> <span>HIGH</span> <span id="high">0.00000</span> </div> <div class="low alert alert-danger col-lg-6"> <span>LOW</span> <span id="low">0.00000</span> </div> <div class="average alert alert-info col-lg-12"> <span>AVERAGE</span> <span id="closing">0.00000</span> </div> <div class="average alert alert-info col-lg-12"> <span>AVERAGE DIFFERENCE</span> <span id="difference">0.00000</span> </div> </div> </div> </body> </html>
And savetodb.php is:
<?php error_reporting(E_ALL); ini_set('display_errors', 1); $ch = curl_init(); // curl_setopt($ch, CURLOPT_URL,"https://api-fxpractice.oanda.com/v3/instruments/EUR_USD/candles?count=100"); curl_setopt($ch, CURLOPT_HTTPGET , 1); //curl_setopt($ch, CURLOPT_POSTFIELDS,$vars); //Post Fields curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); $headers = [ 'Content-Type: application/json;charset=utf-8', 'Authorization: Bearer token-cdf86287f59f25f0abf14e215a5b3cb1', ]; curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); $server_output = curl_exec ($ch); $array = json_decode($server_output,true); curl_close ($ch); //print_r($array); $h = array(); $l = array(); $avg = array(); $con=mysqli_connect("etc","etc","pass","db"); mysqli_query($con,'TRUNCATE TABLE prices'); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } foreach($array['candles'] as $item){ mysqli_query($con,"INSERT INTO prices (low,high,close) VALUES ('".$item['mid']['l']."','".$item['mid']['h']."','".$item['mid']['c']."')"); } mysqli_close($con); ?>
1 个解决方案
解决方案1
0 已采纳 2017-11-21 14:37:50
我通过重组第二个ajax调用来解决了400错误，将其添加为对第一个ajax请求的成功调用：
success: function(data){ console.log('ajax success call begins'); $.ajax({ url: 'savetodb.php', data: {action: 'test'}, type: 'post', success: function(output) { } }) }
并重组PHP页面上的内容以查找POST变量“ action”，如下所示
<?php error_reporting(E_ALL); ini_set('display_errors', 1); if(isset($_POST['action']) && !empty($_POST['action'])) { $action = $_POST['action']; switch($action) { case 'test' : test();break; } } function test(){ // stuff to do here }
Ajax Bad Request 400 Rails
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