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同一两个表上的两个联接

[英]two joins on same two tables

我有这两张桌子。 我想加入这两个表和real_name从我的player有桌子playerAplayerB在我的match表。 所以我尝试了这个。 不幸的是,当我尝试此操作时,我的比赛从46k记录增加到超过一百万条记录,因此我知道这不能正常工作。

SELECT players.player_id, players.real_name, matches.playerA, matches.playerB, matches.scoreA, matches.scoreB
  FROM players
  JOIN matches ON players.player_id = matches.playerA
  JOIN matches m1 ON players.player_id = m1.playerB;

+----------+---------+---------+
| match_id | playerA | playerB |
+----------+---------+---------+
|        1 |       4 |      55 |
|        2 |       2 |      41 |
|        3 |      21 |      41 |
|        4 |       3 |       2 |
|        5 |      41 |       2 |
|        6 |      21 |       3 |
|        7 |       1 |       8 |
|        8 |       1 |       8 |
|        9 |       8 |      19 |
|       10 |      19 |      12 |
+----------+---------+---------+

+-----------+-----------------+
| player_id | real_name       |
+-----------+-----------------+
|         1 | Dong Nyoung Lee |
|         2 | Hyun Woo Jang   |
|         3 | Seung Hyun Lee  |
|         4 | Soo Ho Park     |
|         5 | Lee Sak Won     |
|         6 | Young Suh Yoon  |
|         7 | Yoon Jong Jung  |
|         8 | Dong Hwan Kim   |
|         9 | Tae Hoon Kwon   |
|        10 | Ilyes Satouri   |
+-----------+-----------------+

我添加了要求的内容。

+-----------+------------------------------------+---------+---------+--------+--------+
| player_id | real_name                          | playerA | playerB | scoreA | scoreB |
+-----------+------------------------------------+---------+---------+--------+--------+
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |
|         4 | Soo Ho Park                        |       4 |      55 |      1 |      3 |

如果您打算排行/匹配,我相信您想要的是这样的:

SELECT p1.player_id, p1.real_name, p2_player_id, p2_player_name, 
     m.scoreA, m.scoreB
FROM matches m
JOIN players p1 ON p1.player_id = m.playerA
JOIN players p2 ON p2.player_id = m.playerB

照原样,对于表“ match”中的每个配对,您将获得每个参与比赛的玩家1的行乘以每个参与比赛的运动员2的行。

显示以前运行的查询以及要显示的数据将很有帮助。

您的查询当前正在做的是,对于每个玩家,从他们作为玩家A的每个比赛中加载行,然后从他们作为玩家B的每个比赛中加载行。由于SQL不会“排队”这两个联接,而是交叉乘以它们(即生成它们的每种组合),您可能会为每个玩家ID生成许多行。

如果您要查找的是具有参与者全名和分数的匹配ID表,则该表看起来更像这样:

select m.match_id, pA.full_name, m.scoreA, pB.full_name, m.scoreB from matches m join players pA on pA.player_id = m.playerA join players pB on pB.player_id = m.playerB

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