按工作日名称swift3排序字典数组

Question

我想按工作日名称对根数组进行排序。 就像在根数组的第一个索引上一样，应该是星期日，星期一，星期二等等。

[{

    day = Monday;
    timingValues =     (
                {
            closeHour = 23;
            closeMin = 55;
            day = Monday;
            id = 2;
            openHour = 00;
            openMin = 00;
        }
    );
}, 

{

 day = Tuesday;

    timingValues =     (

                {
            closeHour = 00;
            closeMin = 11;
            day = Tuesday;
            id = 4;
            openHour = 12;
            openMin = 10;
        }
    );
}, {

    day = Sunday;
    timingValues =   (
                {
            closeHour = 23;
            closeMin = 07;
            day = Sunday;
            id = 5;
            openHour = 11;
            openMin = 07;
        }

);

}]

Answer 1

很多力量打开，但你可以得到比较的想法，还需要确保字符串是正确的，我只是在这里做1行作为参考，它不安全，在实际代码中应该做可选检查。

let dictArray = [["day": "Monday", "timingValues" : 1],
                     ["day" : "Tuesday", "timingValues" : 2],
                     ["day" : "Saturday", "timingValues" : 3],
                     ["day" : "Sunday", "timingValues" : 4]]
let b = dictArray.sorted(by: { DateFormatter().weekdaySymbols.index(of: ($0["day"]! as! String))! < DateFormatter().weekdaySymbols.index(of: ($1["day"]! as! String))! })

结果：

[["day": "Sunday", "timingValues": 4], ["day": "Monday", "timingValues": 1], ["day": "Tuesday", "timingValues": 2], ["day": "Saturday", "timingValues": 3]]

Answer 2

首先，你问题中的Dictionary格式与Swift的语法不匹配。 我认为你知道它，并且你有一个具有这种结构的正确的Swift字典。 请参阅此参考 。

接下来，您应该像这样定义工作日的自定义类型（请注意，星期从星期日开始）：

enum Weekday: Int {
    case sunday = 0, monday, tuesday, wednesday, thursday, friday, saturday
}

确保使用此类型创建字典作为日值的键。

鉴于你已经正确设置了所有东西，你应该能够像这样得到排序数组：

let sortedArray = initialArray.sorted { (element0, element1) -> Bool in
    guard let day0 = element0["day"] as? Weekday, let day1 = element1["day"] as? Weekday else {
        // Default behaviour in case you used wrong Weekday type or didn't set it at all 
        return false
    }

    return day0 < day1
}