PHP通过存储过程获取从数据库返回的结果数

Question

我正在尝试使用mysqli_num_rows从数据库中获取结果数，但是我不知道要传递什么参数，因为我正在使用存储过程。 我将发布我的工作。 在我当前的代码中，执行Else。 我是PHP的新手。

<?php

session_start();

include_once  'constants.php';
include_once 'connection.php';

$connection = new database();

$connection->connect();

$email = $_POST['email'];
$password = $_POST['password'];

// Call the login stored procedure
$conn = $connection->query("CALL LoginUser('$email','$password')");

//Check if any users match
$rows = mysqli_num_rows($conn);
if($rows > 0){

// If result was found put information into array
$user = mysqli_fetch_assoc($conn);

//Store all the users info in session variables
$_SESSION['user_id'] = $user['account_id'];
$_SESSION['user_firstName'] = $user['fname'];
$_SESSION['user_lastName'] = $user['lname'];
$_SESSION['user_password'] = $user['password'];
$_SESSION['user_dob'] = $user['dob'];
$_SESSION['user_joinDate'] = $user['joinDate'];
$_SESSION['user_picture'] = $user['picture'];

//Redirect user to logged in home page
header('Location: home.php');

// If no results are found redirect user to noAccount page
} else {
header('Location: noAccount.php');
}


?>

Answer 1

$user = mysqli_fetch_assoc($conn);
    if(!empty($user) > 0){

//Store all the users info in session variables
$_SESSION['user_id'] = $user['account_id'];
$_SESSION['user_firstName'] = $user['fname'];
$_SESSION['user_lastName'] = $user['lname'];
$_SESSION['user_password'] = $user['password'];
$_SESSION['user_dob'] = $user['dob'];
$_SESSION['user_joinDate'] = $user['joinDate'];
$_SESSION['user_picture'] = $user['picture'];

//Redirect user to logged in home page
header('Location: home.php');

// If no results are found redirect user to noAccount page
} else {
header('Location: noAccount.php');
}

mysqli_num_rows期望输出结果。

编辑： num_rows期望查询结果而不是获取的结果。 在这种情况下，我建议您使用我修改过的上述代码。