[英]Looping through elements not working
我想检查this
元素是否具有与所有其他元素匹配的数据属性值,但是循环并不总是有效。
精简下面的代码。
HTML
<div class="list">
<div class="target" data-post-id="1"></div>
<div class="target" data-post-id="2"></div>
<div class="target" data-post-id="1"></div>
<div class="target" data-post-id="1"></div>
</div>
JS(事件绑定到target
类):
if ($(this).data("post-id") == $(this).closest('.list').find('.target').data("post-id")) {
// do stuff
}
显然,我不知道如何正确遍历它。 有什么解决方案?
您可能会使用单线:
if ($(this).closest('.list').find('.target[data-post-id=' + $(this).data("post-id") + ']').not(this).length > 0) {
// there was at least one other element in the list with the same data-post-id as the clicked element
}
我有一个纯JavaScript的答案。 尝试这个,
var divs = document.getElementsByClassName('list')[0].children; function divClick(element) { Array.from(divs).forEach(div => { if(element != div) { if (element.dataset.postId == div.dataset.postId) { console.log("equal"); } else { console.log("not equal"); } } }); }
<div class="list"> <div class="target" onclick="divClick(this)" data-post-id="1">One</div> <div class="target" onclick="divClick(this)" data-post-id="2">Two</div> <div class="target" onclick="divClick(this)" data-post-id="1">Three</div> <div class="target" onclick="divClick(this)" data-post-id="1">Four</div> </div>
在这种情况下,jquery中的.siblings()
会有所帮助,
$(document).ready(function(){ $('.target').click(function(){ $.each($(this).siblings(), (div, element) => { if($(element).data("post-id") == $(this).data("post-id")) { console.log("Equal"); } else { console.log("Not Equal"); } }) }); });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="list"> <div class="target" data-post-id="1">One</div> <div class="target" data-post-id="2">Two</div> <div class="target" data-post-id="1">Three</div> <div class="target" data-post-id="1">Four</div> </div>
这应该为您工作:
<div class="list">
<div class="not-a-sibling">
<div class="target" data-post-id="1"></div>
</div>
<div class="target" data-post-id="2"></div>
<div class="not-a-target">I'M NOT A TARGET, LEAVE ME ALONE!</div>
<div class="target" data-post-id="1"></div>
<div class="target" data-post-id="1"></div>
<div class="target" data-post-id="3"></div>
<div class="target" data-post-id="3"></div>
</div>
假设您基于点击事件-显然,请将其更改为悬停或其他相关内容。
$(document).on('click', '.target', function() {
var clickedTarget = $(this);
var clickedTargetPostId = clickedTarget.data('post-id');
var elementsToCompare = clickedTarget.parents('.list').find('.target').not(this);
elementsToCompare.each(function() {
var elementToComparePostId = $(this).data('post-id');
if (elementToComparePostId === clickedTargetPostId) {
alert('Found a match!');
}
});
});
在这里测试:
https://jsfiddle.net/5wv40vq9/4/
$(document).on('click', '.target', function() {
var _this = this;
$(_this).parents('.list').find('.target').not(this).each(function() {
if ($(this).data('post-id') === $(_this).data('post-id')) {
alert('Found a match!');
}
});
});
你需要这样的东西吗?
var arr1 = [];
var arr2 = [];
$(".target").each(function(){
arr1.push($(this).data("post-id"));
});
$(".target").each(function(index){
var newArray = arr1.slice();
newArray.splice(index, 1); // remove index value from an array, so this index != match its own
console.log(newArray);
if ($.inArray($(this).data("post-id"), newArray ) !== -1){
$(this).text("Has A Match!");
}else{
$(this).text("No Match!");
}
});
Jsfiddle此处: https ://jsfiddle.net/synz/votuqyp0/1/
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