[英]MapStruct QualifiedByName with multiple parameters
我遇到过这样一种情况,我的映射方法有 3 个参数,并且所有这三个参数都用于派生目标类型的属性之一。
我在接口中创建了一个默认映射方法,保留派生属性的逻辑,现在为了调用这个方法,我可以在@Mapping
注释中使用expression = "java( /*method call here*/ )"
。
有没有办法用任何像@qualifiedByName
这样的 mapstruct 注释来做到这@qualifiedByName
,我尝试评论具有表达式属性的注释并使用了qualifiedByName,但它不起作用:
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
//@Mapping(target="qualified",expression = "java( checkQualified (one, projId, code) )")
@Mapping(target="qualified",qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, Integer projId, Integer val, String code);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, Integer projId, Integer val, String code) {
if(one.getProjectId() == projId && one.getVal() == val && one.getCode().equalsIgnoreCase(code)) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
当前 MapStruct 不支持具有多个源属性的映射方法。
但是,在您的情况下,您可以使用 1.2.0 中的@Context
。 据我所知, projId
和code
只是作为映射的助手存在,它们不用于映射目标属性。
所以你可以做这样的事情(理论上应该可以):
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
@Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, @Context Integer projId, @Context String code);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, @Context Integer projId, @Context String code) {
if(one.getProjectId() == projId && one.getCode().equalsIgnoreCase(code)) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
另一种选择是将所有这些属性提取到一个单独的类中并将其传递(这将允许相同类型的多个参数)。
这个类看起来像:
public class Filter {
private final Integer projId;
private final Integer val;
private final String code;
public Filter (Integer projId, Integer val, String code) {
this.projId = projId;
this.val = val;
this.code = code;
}
//getters
}
您的映射器将如下所示:
@Mapper
public interface OneMapper {
@Mapping(target="id", source="one.id")
@Mapping(target="qualified", qualifiedByName="checkQualifiedNamed")
OneDto createOne (One one, @Context Filter filter);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, @Context Filter filter) {
if(one.getProjectId() == filter.getProjId() && one.getVal() == filter.getVal() && one.getCode().equalsIgnoreCase(filter.getCode())) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
然后你可以像这样调用映射器: mapper.createOne(one, new Filter(projId, val, code));
从 1.2 版开始支持: http : //mapstruct.org/documentation/stable/reference/html/#mappings-with-several-source-parameters
例如像这样:
@Mapping(source = "person.description", target = "description")
@Mapping(source = "address.houseNo", target = "houseNumber")
DeliveryAddressDto personAndAddressToDeliveryAddressDto(Person person, Address address);
更新
由于 Mapstruct 允许将多个源参数映射到单个目标,我建议从映射器中提取checkQualified
方法,而不是预先计算结果并使用 checkQualified 方法的结果调用映射器。 Mapstruct 是一个映射库,并不擅长执行任意逻辑。 这并非不可能,但就我个人而言,我看不到它在您的特定情况下增加的价值。
提取逻辑后,您的映射器可能如下所示:
@Mapper
public interface OneMapper {
OneDto toOneDto(One one, Boolean qualified);
}
映射器可以这样使用:
One one = new One(1, 10, 100, "one");
boolean qualified = checkQualified(one, 10, 100, "one");
boolean notQualified = checkQualified(one, 10, 100, "two");
OneDto oneDto = mapper.toOneDto(one, isQualified);
有关完整示例,请参阅: https : //github.com/phazebroek/so-mapstruct/blob/master/src/main/java/nl/phazebroek/so/MapStructDemo.java
您可以创建一个默认方法,该方法使用额外的上下文参数在内部调用 mapstruct 方法。这样,您可以获得 'qualifiedByName' 部分中的所有参数
@Mapper
public interface OneMapper {
default OneDto createOne(One one, Integer projId, Integer val, String code) {
return createOneWithContext(one,porjId,val,code
one,porjId,val,code //as context params
);
}
@Mapping(target="id", source="one.id")
@Mapping(target="qualified",source="one",qualifiedByName="checkQualifiedNamed")
OneDto createOneWithContext (One one, Integer projId, Integer val, String code
@Context One oneAsContext,
@Context Integer projIdAsContext,
@Context Integer valAsContext,
@Context String codeAsContext
);
@Named("checkQualifiedNamed")
default Boolean checkQualified (One one, @Context Integer projId, @Context Integer val, @Context String code) {
if(one.getProjectId() == projId && one.getVal() == val && one.getCode().equalsIgnoreCase(code)) {
return Boolean.TRUE;
}
return Boolean.FALSE;
}
}
```
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