警告：不兼容的指针类型将“char *”传递给“FILE *”类型的参数（又名“struct __sFILE *”）

Question

我正在尝试执行我的代码，但我似乎收到了这个不兼容的警告。

int Read_Data_File(void)
{
    FILE *ptr_file;
    char *end = "0.0.0.0 none";
    char *buf;
    int endLoop = 0;

    ptr_file = fopen("CS222_Inet.txt", "r");


    if (!ptr_file) 
        return 1;

    int i = 0;

    while (!feof(ptr_file)){
        addr[i]=(struct address_t *)malloc(sizeof(struct address_t));
        fscanf(ptr_file,"%s",buf);
        if(!(strcmp(buf, end) == 0)){
            fscanf(buf,"%d %d %d %d %s", &addr[i]->IP1, &addr[i]->IP2,  &addr[i]->IP3, &addr[i]->IP4, addr[i]->name);
            n++;
        }
        i++;
    }

    fclose(ptr_file);
    return 0;
}

我希望这个程序读取文件并将我的结构类型存储到我的 buf 指针中。

警告输出：

project.c:65:11: warning: incompatible pointer types passing 'char *' to
      parameter of type 'FILE *' (aka 'struct __sFILE *')
      [-Wincompatible-pointer-types]
                        fscanf(buf,"%d %d %d %d %s", &addr[i]->IP1, &add...
                               ^~~
/Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.12.sdk/usr/include/stdio.h:250:30: note: 
      passing argument to parameter here
int      fscanf(FILE * __restrict, const char * __restrict, ...) __scanf...
                                 ^

Answer 1

就像错误所说： fscanf期望它的第一个参数是FILE * ，而您将它传递给一个字符缓冲区。 如果要使用scanf系列函数解析字符缓冲区，请使用sscanf